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igor_vitrenko [27]
2 years ago
13

If x varies directly as y and x = 74 when y = 10, find x when y = 4.

Mathematics
1 answer:
Fittoniya [83]2 years ago
5 0

Answer:

The value of x is 21 .

Step-by-step explanation:

We are given that x varies directly as y

--- A

We are given that x = 7 and y = 28

Substitute the values in A

7 = 28k

Now equations becomes :  

y = 84

Hence The value of x is 21 .

#Learn more:

Find the value of y for a given value of x, if y varies directly with x.

If y = −252 when x = 84, what is y when x = 74

Step-by-step explanation:

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-4x + 8 > 12 inequality solution ?
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Answer:

x<-1

Step-by-step explanation:

-4x+8>12

-4x>12-8

-4x>4

x>4/-4

x>-1

x<-1

6 0
3 years ago
Y=x^2-4x-1 in vertex form
belka [17]
The answer is Y= (x-2)^2-5

8 0
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3x+y=4<br> 2x+y=5<br> solve using linear combination
Advocard [28]
Idk what linear combination is but you can solve this way:
3x+y=4
-2x-y=-5
x=-1
3(-1)+y=4
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3 0
3 years ago
Read 2 more answers
If Val walls 1/2 mile for every 3/4 mile she runs if she walked 2 miles how many miles did she run
Usimov [2.4K]
Answer: She ran 3 miles

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6 0
2 years ago
Find the distance between the complex numbers. z1 = 9 - 9i z2 = 10 - 9i
steposvetlana [31]

Answer:

The distance between the two given complex numbers = 9

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<u><em>Step(i):</em></u>-

Given  Z₁ = 9 - 9 i    and Z₂ = 10 -9 i

Let A and B represent complex numbers Z₁ and Z₂ respectively on the argand plane

⇒ A =  Z₁ = x₁ +i y₁ = 9 - 9 i and

    B = Z₂ = x₂+ i y₂ = 10 -9 i

Let (x₁ , y₁) = ( 9, -9)

     (x₂, y₂) = (10, -9)

<u>Step(ii)</u>:-

<em>The distance between the two points are </em>

    A B   =   \sqrt{(x_{2} - x_{1})^{2}+(y_{2} - y_{1})^{2}    }

    A B =   \sqrt{(10 - 1)^{2}+(-9 - (-9))^{2}    }

   AB   = \sqrt{(9)^{2} +(-9+9)^{2} }

 <em> AB    =  √81 = 9</em>

<u><em>Conclusion:-</em></u>

The distance between the two given complex numbers = 9

<u><em></em></u>

3 0
3 years ago
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