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Semenov [28]
3 years ago
6

When a solution is allowed to crystallize slowly, impurities are excluded from the growing crystal structure because: A. The mol

ecules in the crystal lattice are cooler than the solvent and impurities would have too high a melting point to join the lattice.B. The molecules in the crystal lattice are in equilibrium with the molecules in solution and molecules that don't fit well into the lattice (impurities) are likely to return to the solution.C. Impurities could never join the lattice because they are always liquid at room temperature.D. During slow crystallization, impurities are prevented from joining the crystal structure because of their ionic strength.
Chemistry
1 answer:
Oliga [24]3 years ago
4 0

Answer:

B

Explanation:

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Calculate the grams of solute in each of the following solution: 278 mL of 0.038 M Fe2(SO4)3
Goryan [66]

Answer:  4.22 grams of solute is there in 278 ml of 0.038 M Fe_2(SO_4)_3

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in L

Now put all the given values in the formula of molality, we get

0.038M=\frac{n}{0.278L}

n=0.0105mol  

mass of  Fe_2(SO_4)_3 = moles\times {\text {Molar Mass}}=0.0105\times 399.88g/mol=4.22g

Thus 4.22 grams of solute is there in 278 ml of 0.038 M Fe_2(SO_4)_3

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Electrons must be able to flow through a material in order for the material to conduct
djverab [1.8K]

The molecular structure of the solids has lower ability to conduct electricity due to tight holding by nucleus.

<h3>Why molecular solids are poor conductors?</h3>

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What is a good title for this chart?
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Answer:

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Explanation:

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3 years ago
Identify the conjugate acid/base pairs in each of the following equations:
Valentin [98]

Answer:

(a) Pair 1: H₂S and HS⁻

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(b) Pair 1: HSO₄⁻ and SO₄⁻

    Pair 2: NH₃ and NH₄⁺

(c) Pair 1: HBr and Br⁻

    Pair 2: CH₃O⁻ and CH₃OH

(d)  Pair 1: HNO₃ and NO₃⁻

     Pair 2: H₃O⁺

Explanation:

When an acid loses its proton (H⁺), a conjugate base is produced.

When a base accepts a proton (H⁺), it forms a conjugate acid.

(a) H₂S is an acid. When it loses a proton, it forms the conjugate base HS⁻.

    NH₃ is a base. When NH₃ gains a proton, it forms the conjugate acid NH₄⁺

(b) The acid HSO₄⁻ loses a H⁺ ion and forms the conjugate base SO₄²⁻.

     The base NH₃ accepts a H⁺ ion to form the conjugate acid NH₄⁺.

(c) HBr is an acid. When loses the H⁺ ion, it forms the conjugate base Br⁻.

   CH₃O⁻ accepts a H⁺ ion to form the conjugate acid CH₃OH.

(d) HNO₃ loses a proton to form the conjugate base NO₃⁻.

    H₂O gains a proton to form the conjugate acid H₃O⁺.

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How many protons, neutrons, and electrons are there in one atom of 'H ?
kolezko [41]

Answer:

1

Explanation:

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