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3 years ago

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PLEASE HELP ME!!! When two atoms combine to form a compound, one atom pulls electrons from the other atom towards itself. The at

om that pulls electrons is (reduced or oxidized). The atom whose electrons are being pulled is (reduced or oxidized)?

1 answer:

Ainat [17]3 years ago

6 0

Answer:

The pulling atom is oxidized while the pulled atom is reduced. Grade 9 Chemistry

Explanation:

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renal calculi contain crystallized calcium, magnesium, and uric acid. explain why patients with hyperparathyroidism would be at

Phantasy [73]

Patients with hyperparathyroidism would be at risk for developing renal calculi because of high calcium levels excreted by the kidney.

Hyperparathyroidism occurs when there is over secretion of parathyroid hormone by the parathyroid glands.

The parathyroid hormone is responsible for the following in the body:

Release of calcium by bones into the bloodstream.

Absorption of calcium from food by the intestines, and

Conservation of calcium by the kidneys.

Renal calculi are strong masses of stones deposited in the kidneys or urinary bladder.

When there is excess calcium in the blood due to hyperparathyroidism, the kidneys would be over burdened with the excretion of excess calcium.

That extra calcium in the kidney & the urine leads to kidney stone development ( renal calculi).

Therefore, patients with hyperparathyroidism would be at risk for developing renal calculi because of high calcium levels excreted by the kidney.

Learn more here:

brainly.com/question/24153052

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3 years ago

What is the weight of dark matter

Ostrovityanka [42]

Answer:

Knowing this, researchers from the University of Southern Denmark decided to investigate the size of these hypothetical hidden particles. According to the team, dark matter could weigh more than 10 billion billion (10^9) times more than a proton.

Explanation:

If this is true, a single dark matter particle could weigh about 1 microgram, which is about one-third the mass of a human cell (a typical human cell weighs about 3.5 micrograms), and right under the threshold for a particle to become a black hole.

3 0

3 years ago

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An excess of oxygen reacts with 451.4 g of lead, forming 374.7 g of lead(II) oxide. Calculate the percent yield of the reaction.

Stels [109]

Answer: The percent yield of the reaction is 77.0 %

Explanation:

$2Pb+O_2\rightarrow 2PbO$

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

$\text{Number of moles of lead}=\frac{451.4g}{207.2g/mol}=2.18moles$

$\text{Number of moles of lead oxide}=\frac{374.7g}{223.2g/mol}=1.68moles$

According to stoichiometry:

2 moles of $Pb$ produces = 2 moles of $PbO_2$

2.18 moles of $Pb$ is produced by= $\frac{2}{2}\times 2.18=2.18moles$ of $PbO_2$

Mass of $PbO_2$ = $moles\times {\text {Molar mass}}=2.18\times 223.2g/mol=486.6$

percent yield = $\frac{374.7g}{486.6g}\times 100=77.0\%$

3 0

3 years ago

What element has 8 protons 8 neurons and 10 electrons?

mart [117]

Answer:

oxygen ion.

An oxygen ion has 8 protons and 10 electrons.

3 0

3 years ago

Read 2 more answers

Consider the following multistep reaction:

chubhunter [2.5K]

The question is incomplete, here is the complete question:

Consider the following multistep reaction:

C+D⇌CD (fast)

CD+D→CD₂ (slow)

CD₂+D→CD₃ (fast)

C+3D→CD₃

Based on this mechanism, determine the rate law for the overall reaction.

<u>Answer:</u> The rate law for the reaction is $\text{Rate}=k'[C][D]^2$

<u>Explanation:</u>

Rate law is the expression which is used to express the rate of the reaction in terms of the molar concentration of reactants where each term is raised to the power their stoichiometric coefficient respectively from a balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

For the given chemical reaction:

$C+3D\rightarrow CD_3$

The intermediate reaction of the mechanism follows:

<u>Step 1:</u> $C+D\rightleftharpoons CD;\text{ (fast)}$

<u>Step 2:</u> $CD+D\rightarrow CD_2;\text{(slow)}$

<u>Step 3:</u> $CD_2+D\rightarrow CD_3;\text{(fast)}$

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

$\text{Rate}=k[CD][D]$ ......(1)

As, [CD] is not appearing as a reactant in the overall reaction. So, we apply steady state approximation in it.

Applying steady state approximation for CD from step 1, we get:

$K=\frac{[CD]}{[C][D]}$

$[CD]=K[C][D]$

Putting the value of [CD] in equation 1, we get:

$\text{Rate}=k.K[C][D]^2\\\\\text{Rate}=k'[C][D]^2$

Hence, the rate law for the reaction is $\text{Rate}=k'[C][D]^2$

5 0

3 years ago