Answer:
a) the minimun of acetic anhydride required for the reaction is 2.175 g (CH3CO)2O
b) V acetic anhydride = 2.010 mL
Explanation:
C6H4OHCOOH + (CH3CO)2O ↔ C9H8O4 + C2H4O2
⇒ mol salicylic acid = 2.94 g C6H4OHCOOH * ( mol C6H4OHCOOH / 138.121 g ) = 0.0213 mol C6H4OHCOOH
⇒ mol acetic anhydride = 0.0213 mol C6H4OHCOOH * ( mol (CH3CO)2O / mol C6H4OHCOOH ) = 0.0213 mol (CHECO)2O
⇒ g acetic anhydride = 0.0213 mol * ( 102.1 g/mol ) = 2.175 g CH3CO)2O
b) V = 2.175 g (CH3CO)2 * ( mL / 1.082 g ) = 2.010 mL (CH3CO)2O
Answer:
Total mass = 246 g
Explanation:
Given data:
Mass of vinegar = 59 g
Mass of oil = 177 g
Mass of brown sugar = 10 g
Total mass = ?
Solution:
Total mass = masses of [sugar + oil + vinegar]
Total mass = 59 g + 177 g + 10 g
Total mass = 246 g
4. The particles found outside the nucleus are the electrons.
" n " is called principle quantum number.
Here , n = 2
which means ,
number of shells = 2
.: l ( azimuthal quantum no: ) / ( n - 1 ) = 0 , 1
& m ( magnetic quantum number ) = -1 , 0 , +1 .....
s ( spin quantum number ) = ± 1/2 .....
Coming to this question ,
here n = 2 ....
l = 1 ( possible ) .....
ml = -2 [ not possible , because it can only be a number from this set ( -1 , 0 , +1 ) ] .....
.: this set is not possible
