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geniusboy [140]
4 years ago
5

Why is the third equivalence point not observed in the titration curve for phosphoric acid?

Chemistry
1 answer:
BigorU [14]4 years ago
6 0
<span>The third equivalence point is not observed in the titration curve of phosphoric acid because the specific point is concealed due to the rapid ionization of water which in turn forms an hydroxide ion and a molecule called hydronium molecule. The pH value changes more at the first and second points.</span>
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How many individual atoms are represented in the reactants of the equation shown below?
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Answer:

There are 8 hydrogen atoms on the product side in the reaction.

Explanation:

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Which must be the same when comparing 1 mol of oxygen gas, O2, with 1 mol of carbon monoxide gas, CO?
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Answer: C. The Number of Molecules

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Explain three factors that can affect the size of a line in a spectrum.
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If 16.9 kg of Al2O3(s), 57.4 kg of NaOH(l), and 57.4 kg of HF(g) react completely, how many kilograms of cryolite will be produc
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Answer: 69.72 kg of cryolite will be produced.

Explanation:

The balanced chemical equation is:

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To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

moles of Al_2O_3 = \frac{16.9\times 1000g}{102g/mol}=165.7moles

moles of NaOH = \frac{57.4\times 1000g}{40g/mol}=1435moles

moles of HF = \frac{57.4\times 1000g}{20g/mol}=2870moles

As 1 mole of Al_2O_3 reacts with 6 moles of NaOH

166 moles of  Al_2O_3 reacts with = \frac{6}{1}\times 166=996 moles of NaOH

As 1 mole of Al_2O_3 reacts with 12 moles of HF

166 moles of  Al_2O_3 reacts with = \frac{12}{1}\times 166=1992 moles of HF

Thus Al_2O_3 is the limiting reagent.

As 1 mole of Al_2O_3 produces = 2 moles of cryolite

166 moles of  Al_2O_3 reacts with = \frac{2}{1}\times 166=332 moles of cryolite

Mass of cryolite (Na_3AlF_6) = moles\times {\text {molar mass}}=332mol\times 210g/mol=69720g=69.72kg

Thus 69.72 kg of cryolite will be produced.

8 0
3 years ago
What is the formula for vanillic acid​
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the formula for tht is C8H8O4

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