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2 years ago

6 > 3p + 9 could u also show work

Mathematics

2 answers:

Anuta_ua [19.1K]2 years ago

8 0

Answer:

p < -1

Step-by-step explanation:

Original equation:

6 > 3p + 9

Subtract 9 from both sides

The equation should look like this now:

-3 > 3p

Divide both sides by 3 (to separate the 3 from the <em>p</em>)

-1 > p

p < -1

Hope this helps :)

ddd [48]2 years ago

4 0

Answer:-1>p

Step-by-step explanation:

6>3p+9

-9 -9

-3>3p

Divide by 3 on each side

-1>p

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Find four consecutive integers such that twice the sum of the first and third is

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Answer:

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Step-by-step explanation:

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6 0

2 years ago

If y varies jointly as x and the cube of z and y=16 when x=4 and z=2 then y=0.5 when x=-8 and z=-3?

Evgesh-ka [11]

Answer: F (False)

Step-by-step explanation:

Jointly variation has the following form:

y=kxz

Where k is a constant of propotionality.

Substitute values:

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Then the answer is FALSE.

8 0

3 years ago

Read 2 more answers

Karl is putting a frame around a rectangular photograph. The photograph is 14 inches long and 10 inches wide, and the frame is t

Sergeu [11.5K]

<h2>The area of the framed photograph = 1156 $inch^{2}$ </h2>

Step-by-step explanation:

Given,

The length of photograph (l) = 14 inches and

The breadth of photograph (b) = 10 inches

To find, the area of the framed photograph = ?

We know that,

The area of the framed photograph = (l + 2b)(l + 2b)

= (14 + 2 × 10) (14 + 2 × 10) $inch^{2}$

= (14 + 20) (14 + 20) $inch^{2}$

= (34) (34) $inch^{2}$

= 1156 $inch^{2}$

∴ The area of the framed photograph = 1156 $inch^{2}$

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3 years ago

What is 1.6 powered by 2

ss7ja [257]

Answer:

2.56

Step-by-step explanation:

1.6^2 = 1.6 * 1.6 = 2.56

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3 years ago

Suppose there is a pile of quarters dimes and pennies with a total value of $1.07 how much of each coin can be present without b

Korolek [52]

Hello,

Very nice as problem.

2 solutions:
1 quater,8 dimes, 2 pennies
and
3 quaters,3 dimes, 2 pennies

since
107=( 0, 0, 107) but : 100= 0*25+ 0*10+ 100
107=( 0, 1, 97) but : 100= 0*25+ 1*10+ 90
107=( 0, 2, 87) but : 100= 0*25+ 2*10+ 80
107=( 0, 3, 77) but : 100= 0*25+ 3*10+ 70
107=( 0, 4, 67) but : 100= 0*25+ 4*10+ 60
107=( 0, 5, 57) but : 100= 0*25+ 5*10+ 50
107=( 0, 6, 47) but : 100= 0*25+ 6*10+ 40
107=( 0, 7, 37) but : 100= 0*25+ 7*10+ 30
107=( 0, 8, 27) but : 100= 0*25+ 8*10+ 20
107=( 0, 9, 17) but : 100= 0*25+ 9*10+ 10
107=( 0, 10, 7) but : 100= 0*25+ 10*10+ 0
107=( 1, 0, 82) but : 100= 1*25+ 0*10+ 75
107=( 1, 1, 72) but : 100= 1*25+ 1*10+ 65
107=( 1, 2, 62) but : 100= 1*25+ 2*10+ 55
107=( 1, 3, 52) but : 100= 1*25+ 3*10+ 45
107=( 1, 4, 42) but : 100= 1*25+ 4*10+ 35
107=( 1, 5, 32) but : 100= 1*25+ 5*10+ 25
107=( 1, 6, 22) but : 100= 1*25+ 6*10+ 15
107=( 1, 7, 12) but : 100= 1*25+ 7*10+ 5
107=( 1, 8, 2) is good
107=( 2, 0, 57) but : 100= 2*25+ 0*10+ 50
107=( 2, 1, 47) but : 100= 2*25+ 1*10+ 40
107=( 2, 2, 37) but : 100= 2*25+ 2*10+ 30
107=( 2, 3, 27) but : 100= 2*25+ 3*10+ 20
107=( 2, 4, 17) but : 100= 2*25+ 4*10+ 10
107=( 2, 5, 7) but : 100= 2*25+ 5*10+ 0
107=( 3, 0, 32) but : 100= 3*25+ 0*10+ 25
107=( 3, 1, 22) but : 100= 3*25+ 1*10+ 15
107=( 3, 2, 12) but : 100= 3*25+ 2*10+ 5
107=( 3, 3, 2) is good
107=( 4, 0, 7) but : 100= 4*25+ 0*10+ 0

4 0

3 years ago