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MArishka [77]
3 years ago
14

Which of the following is known as the following cycle because it's reservoir is a rock.

Physics
1 answer:
inessss [21]3 years ago
3 0

Letra a obrigadoaijahahavqvqgqgqg

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Please help me - i beg u
oksano4ka [1.4K]

Answer:

516526.863 m

Explanation:

From the question given above, the following data were obtained:

Acceleration due to gravity (g) = 2.24 m/s²

Mass (M) = 8.96×10²¹ Kg

Gravitational constant (G) = 6.67×10¯¹¹Nm²/Kg²

Radius (r) =?

The radius of the planet can be obtained as follow:

g = GM/r²

2.24 = 6.67×10¯¹¹ × 8.96×10²¹ / r²

2.24 = 5.97632×10¹¹ / r²

Cross multiply

2.24 × r² = 5.97632×10¹¹

Divide both side by 2.24

r² = 5.97632×10¹¹ / 2.24

r² = 2.668×10¹¹

Take the square root of both side

r = √2.668×10¹¹

r = 516526.863 m

Thus, the radius of the planet is 516526.863 m

8 0
3 years ago
A driver in a car,originally moving 12.2 m/s, applies the brakes until the car comes to a stop. The car moves a distance of 36.5
mojhsa [17]

First we have to calculate the acceleration of the car,

a =\frac{u-v}{t}

Here, u is initial velocity of the car and its value is given 12.2 m/s and v is final velocity of the car and it comes to stop, so its value zero.

a=\frac{0-12.2 m/s}{t} =\frac{-12.2 \ m/s}{t}.

As during the braking the acceleration is constant, from the kinematic equation,

s=ut + \frac{1}{2} a t^2

Here, s is the distance traveled by the car during braking and its value is given 36. 5 m.

Substituting all the values in kinematic equation, we get

36.5 m =(12.2 m/s) t + \frac{1}{2} (- \frac{12.2 m/s}{t}) t^2 \\\\ 36.5 \ m = (12.2 \ m/s) t -(6.1 \ m/s) t \\\\\ t = \frac{36.5 m}{6.1 m/s} = 5.98 s

Therefore, car will stop after 5.98 s.


8 0
3 years ago
7) Which statement below best describes the motion of the cart under the conditions shown in the image below?
arlik [135]
The cart is going left is your answer
4 0
3 years ago
A student produces a wave in a long spring by
Sliva [168]

Answer: 2

Explanation:

4 0
3 years ago
17. How long does it take a giraffe running at a speed of 33 m/s to run 200 meters !
scZoUnD [109]

Answer:

6600sec

Explanation:

T=sv

T=200m*33m/s

T=6600sec

5 0
3 years ago
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