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3 years ago

What were the patterns that people saw in the sky long ago?

2 answers:

7 0

Long time ago, people saw the constellations as patterns in the sky. They names these patterns and tell stories about them. What people saw laong time ago are just mere patterns which forms animals and shapes. We got the names of our constellations from the Greeks who named the constellations after the mythological heroes and mythological legends.

Serhud [2]3 years ago

6 0

Answer:

There are many patterns:

1) Constellations, that is something like "Patterns" of stars, and people used to give them some bigger meaning than that (as they used to do with almost everything)

2) Time patterns: These are maybe the most useful, an example of this can be that in winter the time that the moon is in the sky is smaller than in the summer, so they already have some information about astronomy, other examples are things like comets and such, that also happened (and keep happening) in periodic time lapses.

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When an object is placed 110 cm from a diverging thin lens, its image is found to be 55 cm from the lens. The lens is removed, a

Kazeer [188]

Explanation:

Given that,

Object distance u= -110 cm

Image distance v= 55 cm

We need to calculate the focal length for diverging lens

Using formula of lens

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}$

Put the value into the formula

$\dfrac{1}{-f}=\dfrac{1}{55}-\dfrac{1}{-110}$

$\dfrac{1}{f}=-\dfrac{3}{110}$

$f=-36.6\ cm$

The focal length of the diverging lens is 36.6 cm.

Now given a thin lens with same magnitude of focal length 36.6 cm is replaced.

Here, The object distance is again the same.

We need to calculate the image distance for converging lens

Using formula of lens

$\dfrac{1}{36.6}=\dfrac{1}{v}-\dfrac{1}{-110}$

Here, focal length is positive for converging lens

$\dfrac{1}{v}=\dfrac{1}{36.6}-\dfrac{1}{110}$

$\dfrac{1}{v}=\dfrac{367}{20130}$

$v=54.85\ cm$

The distance of the image is 54.85 cm from converging lens.

Hence, This is the required solution.

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2 years ago

When two objects collide, the momentum of the system remains constant. This is a statement of ______________.

Fudgin [204]

Conservation of momentum

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3 years ago

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(5, 3) and (7, 3) are two coordinate points for a single object on a position-versus-time graph. Assume time is measured in seco

Maru [420]

Since the y axis stayed consistent, we can assume it did not move at all.
(So your answer would be A)

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3 years ago

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How would the attractive force between two spheres change if the mass of one sphere was doubled?

Dominik [7]

The force of attraction between two objects can be illustrated using Newton's Law of Universal Gravitation.
The relation between the different parameters is shown in the attached image.

Now, from the relation, we can deduce that the force between the two objects is directly proportional to the masses of the two objects.

This means that, if the mass of one object is doubled, then the force between the two objects will also be doubled.

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2 years ago

When you lift an object, you add the energy of lifting to the object.<br> Tor F

PtichkaEL [24]

It's true, when we lift an object we add energy to it.

because, when we lift an object by applying force , the object attains a height and hence the energy gets stored in it, in the form gravitational potential energy .

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2 years ago