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yKpoI14uk [10]
3 years ago
10

What were the patterns that people saw in the sky long ago?

Physics
2 answers:
Lena [83]3 years ago
7 0
Long time ago, people saw the constellations as patterns in the sky.  They names these patterns and tell stories about them. What people saw laong time ago are just mere patterns which forms animals and shapes.  We got the names of our constellations from the Greeks who named the constellations after the mythological heroes and mythological legends.
Serhud [2]3 years ago
6 0

Answer:

There are many patterns:

1) Constellations, that is something like "Patterns" of stars, and people used to give them some bigger meaning than that (as they used to do with almost everything)

2) Time patterns: These are maybe the most useful, an example of this can be that in winter the time that the moon is in the sky is smaller than in the summer, so they already have some information about astronomy, other examples are things like comets and such, that also happened (and keep happening) in periodic time lapses.

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An air-plane has an effective wing surface area of 17.0 m² that is generating the lift force. In level flight the air speed over
Lady bird [3.3K]

Answer:

Explanation:

Given that,

Surface area A= 17m²

The speed at the top v" = 66m/s

Speed beneath is v' =40 m/s

The density of air p =1.29kg/m³

Weight of plane?

Assuming that,

the height difference between the top and bottom of the wind is negligible and we can ignore any change in gravitational potential energy of the fluid.

Using Bernoulli equation

P'+ ½pv'²+ pgh' = P'' + ½pv''² + pgh''

Where

P' is pressure at the bottom in N/m²

P" is pressure at the top in N/m²

v' is velocity at the bottom in m/s

v" is velocity at the top in m/s

Then, Bernoulli equation becomes

P'+ ½pv'² = P'' + ½pv''²

Rearranging

P' — P'' = ½pv"² —½pv'²

P'—P" = ½p ( v"² —v'²)

P'—P" = ½ × 1.29 × (66²-40²)

P'—P" = 1777.62 N/m²

Lift force can be found from

Pressure = force/Area

Force = ∆P ×A

Force = (P' —P")×A

Since we already have (P'—P")

Then, F=W = (P' —P")×A

W = 1777.62 × 17

W = 30,219.54 N

The weight of the plane is 30.22 KN

5 0
3 years ago
Read 2 more answers
A proton having an initial velvocity of 20.0i Mm/s enters a uniform magnetic field of magnitude 0.300 T with a direction perpend
nikitadnepr [17]

The radius of curvature of the proton's path while in the field is 66.67  × 10^{-2}.

b) Let R = radius curvature of protons path. Then,

relation b/w B, R, and v is: -

B = mv/eR\\R=mv/eB

R=\frac{1.6*10^{-27} * 20*10^{6}}{1.6*10^{-19}*0.3 }

R =66.67× 10^{-2}

Hence, the radius of curvature of the proton's path while in the field is 66.67 × 10^{-2}.

<h3>What do you mean by Magnetic field?</h3>

The magnetic influence on moving electric charges, electric currents and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field.  The magnetic field of a permanent magnet pulls on ferromagnetic substances like iron and attracts or repels other magnets. A magnetic field that varies with location will also exert a force on a variety of non-magnetic materials by changing the velocity of those particles' outer electrons. Electric currents, like those utilized in electromagnets, and electric fields that change in time produce magnetic fields that surround magnetized things.

To know more about Magnetic Field visit:

brainly.com/question/14848188

#SPJ4

5 0
1 year ago
A wheel starts from rest and has an angular acceleration that is given by α (t) = (6.0 rad/s4)t2. After it has turned through 10
marissa [1.9K]

Answer:

75 rad/s

Explanation:

The angular acceleration is the time rate of change of angular velocity. It is given by the formula:

α(t) = d/dt[ω(t)]

Hence: ω(t) = ∫a(t) dt

Also, angular velocity is the time rate of change of displacement. It is given by:

ω(t) = d/dt[θ(t)]

θ(t) = ∫w(t) dt

θ(t) = ∫∫α(t) dtdt

Given that: α (t) = (6.0 rad/s4)t² = 6t² rad/s⁴. Hence:

θ(t) = ∫∫α(t) dtdt

θ(t) = ∫∫6t² dtdt =∫[∫6t² dt]dt

θ(t) = ∫[2t³]dt = t⁴/2 rad

θ(t) = t⁴/2 rad

At θ(t) = 10 rev = (10 *  2π) rad = 20π rad, we can find t:

20π = t⁴/2

40π = t⁴

t = ⁴√40π

t = 3.348 s

ω(t) = ∫α(t) dt = ∫6t² dt = 2t³

ω(t) = 2t³

ω(3.348) = 2(3.348)³ = 75 rad/s

7 0
3 years ago
Of the planets with atmospheres, which is the warmest?<br> a. Venusb. Earthc. Marsd. Jupiter
tangare [24]

The Atmosphere in Jupiter is full of gases that move at high speeds in giant eddies. Its atmosphere consists mostly of gases such as hydrogen that generate a temperature fluctuation of around 128K.

On Earth, due to the protection of the Ozone Layer and the presence of Nitrogen and Oxygen, the temperature fluctuates by an average of 300K.

In the case of Mars, its atmosphere is thin, mostly composed of Carbon Dioxide and Diatomic Nitrogen, which allow a temperature oscillation of 210K.

In contrast, the atmosphere of Venus is thick and is composed of carbon dioxide that does not allow the sun's rays to escape, generating an extreme 'greenhouse effect' with temperatures ranging from 737K,

Correct Answer is A.

7 0
3 years ago
The repeal of the Trustee's ban on slavery boosted Georgia's economy by
Leviafan [203]
The right answer for the question that is being asked and shown above is that: "B) allowing Carolina planters to expand rice cultivation into Georgia's lowlands."
-I hope this is the answer you are looking for.


8 0
3 years ago
Read 2 more answers
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