1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zzz [600]
3 years ago
12

If you're falling in a forest and there's nobody around, do you ever really crash, or even make a sound?

Physics
2 answers:
svp [43]3 years ago
8 0

Answer:

If u are falling then yes

Explanation:

zalisa [80]3 years ago
7 0

Answer:

yes bc there are branches and twigs surrounding you

Explanation:

♡♡♡please mark as brainliest♡♡♡

You might be interested in
A sprinter accelerates from rest to 10.0 m/s in 1.35 s l. What is her acceleration?
ale4655 [162]

Answer:

dsfsdfgfdsggfgsgsfsfgfsgffsfgfgfgf

Explanation:

sgdfggsfdsgfgsgsmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

8 0
3 years ago
Which of these is NOT a possible type of energy transformation?
Orlov [11]

to be franc i really think the answer is B

6 0
3 years ago
During a free fall Swati was accelerating at -9.8m/s2. After 120 seconds how far did she travel? Use the formula =1/2 *
marta [7]
Distance fallen = 1/2 ( V initial + V final ) *t
We know
a = -9.8 m/s2
t=120s

To find distance fallen, we need to find V final
Use the equation
V final = V initial + a*t
Substitute known values
V final = 0 + (-9.8)(120)
V final = -1176 m/s

Then plug known values to distance fallen equation
Distance fallen = 1/2 ( 0 + 1176 )(120)
= 1/2(1776)(120)
=106,560 m

This way plugging into distance equation is actually the long way. A faster way is to plug the values into
Distance fallen = V initial * t + 1/2(a*t)
We won't need to find V final using another equation.

But anyways, good luck!



4 0
3 years ago
HELP WILL MARK BRAINLIEST!!
kherson [118]

Answer:15

Explanation:

8 0
3 years ago
One gram of Uranium averages release 1.01 KJ (10^7) of energy. How much mass could be converted to energy to release this much e
frutty [35]

Answer:

The amount of mass that needs to be converted to release that amount of energy is 1.122 X 10^{-7}  kg

Explanation:

From Albert Einstein's Energy equation, we can understand that mass can get converted to energy, using the formula

E= \Delta mc^{2}

where \Delta m = change in mass

c = speed of light = 3 \times 10 ^{8}m/s

Making m the subject of the formula, we can find the change in mass to be

\Delta m = \frac{E}{c^{2}}= \frac{1.01 \times 10^{3} \times 10^{7}}{(3 \times 10^{8})^{2}}= 1.122 \times 10 ^{-7}kg

There fore, the amount of mass that needs to be converted to release that amount of energy is 1.122 X 10 ^-7 kg

5 0
3 years ago
Other questions:
  • A metal object is four feet away from a magnet. If you move the object two feet closer toward the
    8·1 answer
  • The Lamborghini Huracan has an initial acceleration of 0.75g. Its mass, with a driver, is 1510 kg.
    13·1 answer
  • I really need help with this
    5·1 answer
  • Transparent
    11·1 answer
  • A balloon is negatively charged by rubbing and then clings to a wall. does this mean that the wall is positively charged? why or
    7·2 answers
  • The frequency of a sound wave in water is 15,000 Hz, and the sound wave travels through water at a speed of 1,500 m/s. What is t
    8·1 answer
  • State the objects in the universe that reflect light from stars
    14·1 answer
  • 1. If an object that stands 3 centimeters high is placed 12 centimeters in front of a plane
    13·1 answer
  • Why the fortune tellers never win the lottery
    10·1 answer
  • Explore how archemides principle is applied in building a ship and submarine​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!