Before going to answer this question first we have to know the fundamental principle of magnetism.
A magnet have two poles .The important characteristic of a magnet is that like poles will repel each other while unlike poles will attract each other.
Through this concept the question can be answered as explained below-
A-As per first option the side of magnet A is repelled by the south pole of magnet B. Hence the pole of a must be south .It can't be north as it will lead to attraction.
B-The side of magnet A is repelled by the north pole of magnet B. Hence the side of A must be north pole.It can't be a south pole.
C-The side of magnet A is attracted by the south pole of magnet B .Hence the side of magnet A must be north.Hence this is right
D-The side of magnet A is attracted by the north pole of magnet B. Hence the side of A must south.It can't be north as it will lead to repulsion.
Hence the option C is right.
Plug in the corresponding values into y = mx + b
8.18 in for y
1.31 in for m
17.2 in for b
8.18 = 1.31x + 17.2
Now bring 17.2 to the left side by subtracting 17.2 to both sides (what you do on one side you must do to the other). Since 17.2 is being added on the right side, subtraction (the opposite of addition) will cancel it out (make it zero) from the right side and bring it over to the left side.
8.18 - 17.2 = 1.31x
-9.02 = 1.31x
Then divide 1.31 to both sides to isolate x. Since 1.31 is being multiplied by x, division (the opposite of multiplication) will cancel 1.31 out (in this case it will make 1.31 one) from the right side and bring it over to the left side.
-9.02/1.31 = 1.31x/1.31
x ≈ -6.8855
x is roughly -6.89
Hope this helped!
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If they both are moving with the same speed and direction
i.e. covering the same distance in the same time interval in the same direction
Answer:
The answer is "
".
Explanation:
Cavity and benzene should be extended in equal quantities.
The resonant frequency of a circuit is the frequency 
at which the equivalent impedance of a circuit is purely real (the imaginary part is null).
Mathematically this frequency is described as
Where
L = Inductance
C = Capacitance
Our values are given as
Replacing we have,
From this relationship we can also appreciate that the resonance frequency infers the maximum related transfer in the system and that therefore given an input a maximum output is obtained.
For this particular case, the smaller the capacitance and inductance values, the higher the frequency obtained is likely to be.
