Answer:
9/5 units²
Step-by-step explanation:
Area of a square=s²
A=(3/5)²
A=9/25
Answer:
w = -7.04 and 1.705
Step-by-step explanation:
First lets distribute.
We have 8w-6w(w-4), so let's distribute the -6w to w and -4
8w-6w^2+24w = 2(w+9)
Now for the other side we distribute 2 to w and 9
8w-6w^2+24w = 2w +18
Now we combine like terms
6w^2+32w = 2w +18
Carry both 2w and 18 to the other side
6w^2 +30w -18 = 0
Now we can factor the equation, i used the quadratic method which is x= -b+- the square root of b^2-4ac /2a (in this case x would be w)
Plugging that in:
x= -32 +- square root of 32^2 -4(6 * -18) / 2(6)
-32 +- square root of 1024 +1728 / 12
-32 +- square root of 2752 /12
-32 +- 52.46 /12
x = -32 - 52.46/12 and -32 + 52.46/12
x= -84.46/12 and 20.46/12
x= -7.04 and 1.705
so w = -7.04 and 1.705
Sorry this was so complicated, but I hope this helps
Density is the measurement of the amount of mass per unit of volume.
In this case we should calculate the density of prairie dog burrows on a square field. This is a surface charge density.It is defined as the total amount of units q per km^2.
to calculate<span> the </span>density of prairie dog burrows, we should divide the total number of prairie dog burrows in the field <span>by the size of the field. Thus,
</span><span>
</span>prairie dog <span>burrows in square kilometers= number of dog burrows/ size of the field
size of the field=0.9*0.9=900*900=180000m^2
1980/180000</span><span> m^2= 0.011 dog burrows in square meter
11 dogs in square kilometer</span>
You X to the second power.. 4 to the second power is 16 and 16-16=0 so x=4
