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3 years ago

How many bonding electrons are in the lewis structure of carbon monoxide, co?

Chemistry

2 answers:

arsen [322]3 years ago

6 0

There are six (6) bonding electrons are in the lewis structure of carbon monoxide (CO).
In Lewis structure, there are ten (10) valence electrons of Carbon monoxide (CO). For lewis structure we need a triple bond between carbon and oxygen, so when electrons made a triple bond it means there is six bonding electrons in lewis structure of carbon monoxide.

Georgia [21]3 years ago

5 0

Answer:

Explanation:

The Lewis structure represents the valence electrons at the atoms, which ones are shared and the lone pairs. Carbon is at group 4 at the periodic table, and so has 4 electrons in the valence shell; oxygen is at group 6, and so has 6 electrons at the valence shell.

That compound is an exception of the octet rule. A triple bond is done between the atoms, and so, 3 electrons of carbon are shared and 3 electrons of oxygen are shared. Thus, there are 6 bonding electrons, as shown below in red.

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PLEASE ANSWER I AM BEGGING

TiliK225 [7]

Taking into account the definition of dilution:

you have to use 8.23 mL of a stock solution of 7.00 M HNO₃ to prepare 0.120 L of 0.480 M HNO₃.
If you dilute 20.0 mL of the stock solution to a final volume of 0.270 L , the concentration of the diluted solution is 0.518 M.

<h3>Dilution</h3>

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

Ci: initial concentration
Vi: initial volume
Cf: final concentration
Vf: final volume

<h3>Volume of stock solution</h3>

In this case, you know:

Ci= 7 M
Vi= ?
Cf= 0.480 M
Vf= 0.120 L

Replacing in the definition of dilution:

7 M× Vi= 0.480 M× 0.120 L

Solving:

Vi= (0.480 M× 0.120 L)÷ 7 M

<u><em>Vi= 0.00823 L= 8.23 mL</em></u> (being 1 L= 1000 mL)

Finally, you will need 8.23 mL of the stock solution.

<h3>Concentration of the diluted solution</h3>

In this case, you know:

Ci= 7 M assuming the stock solution is 7.00 M HNO₃
Vi= 20 mL= 0.02 L
Cf= ?
Vf= 0.270 L

Replacing in the definition of dilution:

7 M× 0.02 L= Cf× 0.270 L

Solving:

(7 M× 0.02 L)÷ 0.270 L= Cf

Finally, the concentration is 0.518 M.

Learn more about dilution:

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5 0

1 year ago

Which particle makes the atom an unstable isotope?

Galina-37 [17]

Instability of an atoms nucleus can result from an excess of either neutrons or protons . So neutrons and protons .

6 0

2 years ago

Which term represents the fixed proportion of elements in a compound

Gekata [30.6K]

Answer:

Chemical formula.

Explanation:

A chemical formula have fix proportion of atoms of elements.

Chemical formula:

A chemical formula is the way of presenting the chemical proportion of atoms of those elements, that combine to form a compound.

For example:

Water consist of two atom of hydrogen and one atom of oxygen. The atoms of both elements combine to form a compound i.e water. The atoms of both elements always combine in a fixed ratio which is 2:1 in molecule of water.

H₂O

2:1

Carbon dioxide consist of two atom of oxygen and one atom of carbon. The atoms of both elements combine to form a compound i.e carbon dioxide. The atoms of both elements always combine in a fixed ratio which is 1:2 in molecule of carbon dioxide .

CO₂

1;2

5 0

3 years ago

How do we measure the mass of an extrasolar planet?

Degger [83]

To determine a planet's mass, astronomers typically measure the minuscule movement of the star caused by the gravitational tug of an orbiting planet. For planets the massof Earth detecting such a tiny tug is extraordinarily challenging with current technology

4 0

3 years ago

How many moles of gold are there in 3.73 x 10^24 atoms of gold?

BARSIC [14]

Answer:

6.2moles of Gold

Explanation:

To solve this problem, we are going to use the mole concept approach.

Given that;

Number of atoms of gold is 3.73 x 10²⁴ atoms

Now;

In 1 mole of any substance, we have 6.02 x 10²³ atoms;

So;

If there 6.02 x 10²³ atoms in 1 mole of any substance;

3.73 x 10²⁴ atoms will contain $\frac{3.73 x 10^{24} }{6.02 x 10^{23} }$ = 6.2moles of Gold

4 0

2 years ago