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3 years ago

How many bonding electrons are in the lewis structure of carbon monoxide, co?

Chemistry

2 answers:

arsen [322]3 years ago

6 0

There are six (6) bonding electrons are in the lewis structure of carbon monoxide (CO).
In Lewis structure, there are ten (10) valence electrons of Carbon monoxide (CO). For lewis structure we need a triple bond between carbon and oxygen, so when electrons made a triple bond it means there is six bonding electrons in lewis structure of carbon monoxide.

Georgia [21]3 years ago

5 0

Answer:

Explanation:

The Lewis structure represents the valence electrons at the atoms, which ones are shared and the lone pairs. Carbon is at group 4 at the periodic table, and so has 4 electrons in the valence shell; oxygen is at group 6, and so has 6 electrons at the valence shell.

That compound is an exception of the octet rule. A triple bond is done between the atoms, and so, 3 electrons of carbon are shared and 3 electrons of oxygen are shared. Thus, there are 6 bonding electrons, as shown below in red.

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15. Which characteristic of a substance will NOT

Andrej [43]

Boiling point. Hope this helps

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2 years ago

Under standard-state conditions, which of the following species is the best reducing agent? a. Ag+ b. Pb c. H2 d. Ag e. Mg2+

eimsori [14]

Answer: The correct answer is Option b.

Explanation:

Reducing agents are defined as the agents which help the other substance to get reduced and itself gets oxidized. They undergo oxidation reaction.

$X\rightarrow X^{n+}+ne^-$

For determination of reducing agents, we will look at the oxidation potentials of the substance. Oxidation potentials can be determined by reversing the standard reduction potentials.

For the given options:

Option a: $Ag^+$

This ion cannot be further oxidized because +1 is the most stable oxidation state of silver.

Option b: $Pb$

This metal can easily get oxidized to $Pb^{2+}$ ion and the standard oxidation potential for this is 0.13 V

$Pb\rightarrow Pb^{2+}+2e^-;E^o_{(Pb/Pb^{2+})}=+0.13V$

Option c: $H_2$

This metal can easily get oxidized to $H^{+}$ ion and the standard oxidation potential for this is 0.0 V

$H_2\rightarrow 2H^++2e^-;E^o_{(H_2/H^{+})}=0.0V$

Option d: $Ag$

This metal can easily get oxidized to $Ag^{+}$ ion and the standard oxidation potential for this is -0.80 V

$Ag\rightarrow Ag^{+}+e^-;E^o_{(Ag/Ag^{+})}=-0.80V$

Option e: $Mg^{2+}$

This ion cannot be further oxidized because +2 is the most stable oxidation state of magnesium.

By looking at the standard oxidation potential of the substances, the substance having highest positive $E^o$ potential will always get oxidized and will undergo oxidation reaction. Thus, considered as strong reducing agent.

From the above values, the correct answer is Option b.

8 0

3 years ago

Peut-on être exact sans être précis?

Evgesh-ka [11]

Answer:

I think you can.

8 0

3 years ago

How many moles of oxygen gas, o2, are in a storage tank with a volume of 1.000×105 l at stp?

Mumz [18]

STP means standard temperature and pressure which is equivalent to 273 K and 1 atm, respectively. Assuming ideal gas behavior, the solution for this problem is as follows:

PV = nRT
Solve for n,
n = RT/PV
n = (0.0821 L-atm/mol-K)(273 K)/(1 atm)(1×10⁵ L)
n = 2.24×10⁻⁴ moles

6 0

3 years ago

Read 2 more answers

An atom has 9 electrons and 9 protons at the start. If it loses 2 electrons, the net charge on the atom will be 8-2-2+8+. If the

Mrrafil [7]

Answer: 1) p⁺ = 22; number of protons.

e⁻ = 19 - 1 = 18; number of electrons.

Net charge is +4, because atom has 4 protons more than electrons.

Proton is a subatomic particle with a positive electric charge of +1e elementary charge.

2) p⁺ = 22; number of protons.

e⁻ = 19 + 3 = 22; number of electrons.

Net charge is 0 (neutral charge), because atom has same number of protons and electrons.

Hope this helps :)

4 0

3 years ago