Answer:11.19
Explanation:
And one mole of a hydrogen atom is of 1.008 grams. So, 2 hydrogen moles weighs 2.016 grams. Hence, one mole of water has 2.016 grams of hydrogen mole. Therefore, the percentage composition of hydrogen would be 2.016/18.0152 = 11.19%.
Answer:
Im confused. Do you need help with something?
Explanation:
<span>Data:
1) molar
mass: 58.0714 g.
2) mass analysis
C: 18 g
H: 3 g
O: 8 g.
Solution
</span>
<span>What is the percent composition of all the components in the liquid?
mass of C + mass of H + mass of O = 18g + 3g + 8g = 29 g
Percent composition:
C: (18g / 29g) * 100 = 62%
H: (3g / 29g) * 100 = 10%
O: (8g / 29g) * 100 = 28%
--------------
Total 100%
What is the empirical formula of the compound?
Convert masses to number of moles by dividing each mass by the atomic mass of the correspondant element:
C: 18 g/ 12.0 g/mol = 1.5 mol
H: 3 g / 1.0 g/mol = 3 mol
O: 8 g / 16 g/mol = 0.5 mol
Divide each number of moles by the smaller, i.e. 0.5 mol
=> C: 1.5 mol / 0.5 mol = 3 mol
=> H: 3 mol / 0.5 mol = 6 mol
=> O: 0.5 mol / o.5 mol = 1 mol
=> Empirical formula: C3 H6 O
What is the molecular formula of the unknown liquid?
First,calculate the molar mass of the empirical formula:
C3 H6 O => 3 * 12 g/mol + 6*1 g/mol + 16 g/mol = 58 g/ mol
Secont, given that the molar mass is the same that the empirical mass, the molecular formula is the same empirical formula.
=> Molecular formula = C3 H6 O.
This compound has been
identified as a ketone.
Go online and figure out the name of this
compound.
It is easy to find that this compound is propanone or acetone (both names are valid).
Now you can go online and find its characteristics and common uses.
Can you identify
the killer from this information? How?
Likely they think you can presume that the killer is the actress, because women use acetone regularlty to remove the nail polish.
</span>
The pressure of 1.27 L of a gas at 288°C, if the gas had a volume of 875 ml at 145 kPa and 176°C is 1.195 atm.
<h3>What is ideal gas equation?</h3>
Ideal gas equation of any gas will be represented as:
PV = nRT, where
P = pressure
V = volume
n = moles
R = universal gas constant
T = temperature
First we calculate the moles of gas, when the volume of gas 875 ml at
145 kPa and 176°C as:
n = (1.431atm)(0.875L) / (0.082L.atm/K.mol)(449.15K)
n = 1.252 / 36.83 = 0.033 moles
Now we measure the pressure of 0.033 moles of gas of 1.27 L of a gas at 288°C as:
P = (0.033mol)(0.082L.atm/K.mol)(561K) / (1.27L) = 1.195 atm
Hence required pressure of gas is 1.195 atm.
To know more about ideal gas equation, visit the below link:
brainly.com/question/555495
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