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xeze [42]
2 years ago
11

An atom has 9 electrons and 9 protons at the start. If it loses 2 electrons, the net charge on the atom will be 8-2-2+8+. If the

atom instead gains 4 electrons, the net charge will be 5-4-4+5+
Chemistry
1 answer:
Mrrafil [7]2 years ago
4 0

Answer: 1) p⁺ = 22; number of protons.

e⁻ = 19 - 1 = 18; number of electrons.

Net charge is +4, because atom has 4 protons more than electrons.

Proton is a subatomic particle with a positive electric charge of +1e elementary charge.

2) p⁺ = 22; number of protons.

e⁻ = 19 + 3 = 22; number of electrons.

Net charge is 0 (neutral charge), because atom has same number of protons and electrons.

Hope this helps :)

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A student notices that after two chemicals are mixed together the temperature of the mixture is higher than the temperature of t
swat32

Answer: exothermic

EXPLANATION: any process in which heat energy is released is called an exothermic process. For example burning of wood produces heat, so combustion of wood is an exothermic process.

When chemicals were not mixed they were at room temperature and when we mix them exothermic reaction took place and heat was released which raised the temperature of mixture.

7 0
3 years ago
Which of the following could be true of two species that have a competitve ralationship in the same ecosystems Help me out pleas
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The answer is b. as a whole, the species is mutually beneficial to carry on each others traits and exist in the same ecosystem.
6 0
3 years ago
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4 0
3 years ago
For the overall reaction below, which of the following is the correctly written rate law? Overall reaction: O3(g)+2NO2(g)→N2O5(g
zavuch27 [327]

Answer: Rate=k[O_3][NO_2]^2

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

O_3(g)+NO_2(g)\rightarrow NO_3(g)+O_2(g)   slow

NO_3(g)+NO_2(g)\rightarrow N_2O_5(g)   fast

To determine the net chemical equation, we will simply add the above two equations, we get:

O_3(g)+2NO_2(g)\rightarrow N_2O_5(g)+O_2(g)

Rate=k[O_3][NO_2]^2

Order with respect to O_3 is 1 and Order with respect to NO_2 is 2.

Thus the rate law will be:  Rate=k[O_3][NO_2]^2

6 0
3 years ago
A 5.000 g mixture contains strontium nitrate and potassium bromide. Excess lead(II) nitrate solution is added to precipitate out
scZoUnD [109]

<u>Answer:</u> The mass percent of potassium bromide in the mixture is 9.996%

<u>Explanation:</u>

  • To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

<u>For lead (II) bromide:</u>

Given mass of lead (II) bromide = 0.7822 g

Molar mass of lead (II) bromide = 367 g/mol

Putting values in equation 1, we get:

\text{Moles of lead (II) bromide}=\frac{0.7822g}{367g/mol}=0.0021mol

  • The chemical equation for the reaction of lead (II) nitrate and potassium bromide follows:

2KBr+Pb(NO_3)_2\rightarrow PbBr_2+2KNO_3

By Stoichiometry of the reaction:

1 mole of lead (II) bromide is produced from 2 moles of potassium bromide

So, 0.0021 moles of lead (II) bromide will be produced from = \frac{2}{1}\times 0.0021=0.0042mol of potassium bromide

  • Now, calculating the mass of potassium bromide by using equation 1, we get:

Molar mass of KBr = 119 g/mol

Moles of KBr = 0.0042 moles

Putting values in equation 1, we get:

0.0042mol=\frac{\text{Mass of KBr}}{119g/mol}\\\\\text{Mass of KBr}=0.4998g

  • To calculate the percentage composition of KBr in the mixture, we use the equation:

\%\text{ composition of KBr}=\frac{\text{Mass of KBr}}{\text{Mass of mixture}}\times 100

Mass of mixture = 5.000 g

Mass of KBr = 0.4998 g

Putting values in above equation, we get:

\%\text{ composition of KBr}=\frac{0.4998g}{5.000g}\times 100=9.996\%

Hence, the percent by mass of KBr in the mixture is 9.996 %

5 0
3 years ago
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