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xeze [42]
3 years ago
11

An atom has 9 electrons and 9 protons at the start. If it loses 2 electrons, the net charge on the atom will be 8-2-2+8+. If the

atom instead gains 4 electrons, the net charge will be 5-4-4+5+
Chemistry
1 answer:
Mrrafil [7]3 years ago
4 0

Answer: 1) p⁺ = 22; number of protons.

e⁻ = 19 - 1 = 18; number of electrons.

Net charge is +4, because atom has 4 protons more than electrons.

Proton is a subatomic particle with a positive electric charge of +1e elementary charge.

2) p⁺ = 22; number of protons.

e⁻ = 19 + 3 = 22; number of electrons.

Net charge is 0 (neutral charge), because atom has same number of protons and electrons.

Hope this helps :)

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mixture: a combination of two or more elements of compound which are not chemically bonded

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How manymoles of each ion are present in 175 mL of 0.147 M Fe2(SO4)3?
lilavasa [31]

Answer: 0.0257 moles of Fe^{3+}  and 0.0257 moles of SO_4^{2-}

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{moles}{\text {Volume in L}}

moles of  Fe_2(SO_4)_3=Molarity\times {\text {Volume in L}}=0.147\times 0.175L=0.0257moles

The balanced reaction for dissociation will be:

Fe_2(SO_4)_3\rightarrow Fe^{3+}+SO_4^{2-}

According to stoichiometry:  

1 mole of Fe_2(SO_4)_3 gives 1 mole of Fe^{3+}  and 1 mole of SO_4^{2-}

Thus there will be 0.0257 moles of Fe^{3+}  and 0.0257 moles of SO_4^{2-}

8 0
3 years ago
Silver nitrate solution reacts with calcium chloride solution according to the equation: 2 AgNO3 + CaCl2 → Ca(NO3)2 + 2 AgCl All
HACTEHA [7]

Answer:

14.33 g

Explanation:

Solve this problem based on the stoichiometry of the reaction.

To do that we need the molecular weight of the masses involved and then calculate the number of moles, find the limiting reagent and  finally calculate the mass of AgCl.

                      2 AgNO₃   + CaCl₂    ⇒   Ca(NO₃)₂   + 2 AgCl

mass, g                  6.97        6.39                                     ?

MW ,g/mol         169.87      110.98                                  143.32

mol =m/MW           0.10         0.06                                    0.10

From the table above AgNO₃ is the limiting reagent and we will produce 0.10 mol AgCl which is a mass :

0.10 mol x 143.32 g/mol = 14.33 g

5 0
3 years ago
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