Answer:
the fuel efficiency in kilometers per liter is 16.561 kilometer per liter
Explanation:
The computation of the full efficiency in kilometers per liter is shown below:
39.0 miles ÷ gallon = (39.0 miles ÷ gallon) × (1.6094 km ÷ 1 miles) × (1 gallon ÷ 3.79 L)
Now cut the opposite miles and gallons
So, the fuel efficiency would be
= 16.561 kilometers per liter
Hence, the fuel efficiency in kilometers per liter is 16.561 kilometer per liter
The answer would be KMnO4, please let me know if you would like me to explain how i got this
Answer:- B. 4.65 g.
Solution:- The given balanced equation is:

It asks to calculate the mass of silver sulfide formed by when 0.0150 liters of 2.50 M of silver nitrate are used.
Moles of silver nitrate are calculated on multiplying it's liters by its molarity and then on multiplying by mol ratio, the moles of silver sulfide are calculated. These moles are multiplied by the molar mass to convert to the grams.
Molar mass of
= 2(107.87)+32.06 = 247.8 g per mol
The dimensional set up for the complete problem is:

= 
So, the correct choice is B. 4.65 g.
We need to know the number of molecules which is number of moles * Avogadro’s number
So
We need to compare number of moles because Avogadro’s numbers is constant for all
We’ll start with Nitrogen gas : 14g/28g.mol=0.5 mole
For NH3 : 3.4g / (14+3)g.mol= 0.2 mol
For NO. : 15g/(14+16)g.mol = 0.5 mol
For O2 : 64g/32 g.mol = 2 mol
For SO2: 32g /( 32+32) g.mol = 0.5mol
For H2. : 1g/ 2g.mol = 0.5 mol
So
H2& SO2 & NO have the same number of moles of N2 and the same number of molecules of N2