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Tanzania [10]
3 years ago
5

Why is the solvation energy negative? a) bonds are being created b) bonds are breaking

Chemistry
1 answer:
IrinaVladis [17]3 years ago
3 0

Answer:

your answer will be b) bonds are breaking

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Draw the products of the complete hydrolysis of an acetal. Draw all products of the reaction.
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2 years ago
Liquid hexane CH3CH24CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. Suppose
Elanso [62]

Answer:

The leftover is 15 g of oxygen rather than liquid hexane as the fuel limits the reaction.

Explanation:

Hello!

In this case, since the described combustion reaction is:

C_6H_{14}(l)+\frac{19}{2} O_2(g)\rightarrow 6CO_2(g)+7H_2O(g)

Thus, since 5.2 g of hexane (86.2 g/mol) is reacted with 33.0 g of oxygen (32.0 g/mol) we can compute the mass of hexane that was actually consumed via stoichiometry with oxygen (1:19/2 mole ratio):

m_{C_6H_{14}}^{consumed \ by\ O_2}=33.0gO_2*\frac{1molO_2}{32.0gO_2}*\frac{1molC_6H_{14}}{\frac{19}{2}gO_2 }  *\frac{86.2gC_6H_{14}}{1molC_6H_{14}} \\\\m_{C_6H_{14}}^{consumed \ by\ O_2}=9.36gC_6H_{14}

It is proved then than the hexane won't have any leftover but oxygen does, as shown below:

m_{O_2}^{consumed \ by\ C_6H_{14}}=5.2gC_6H_{14}*\frac{1molC_6H_{14}}{86.2gC_6H_{14}} *\frac{\frac{19}{2}molO_2 }{1molC_6H_{14}} *\frac{32.0gO_2}{1molO_2} \\\\m_{O_2}^{consumed \ by\ C_6H_{14}}=18g

It means the leftover of oxygen is:

m_{O_2}^{leftover}=33g-18g\\\\m_{O_2}^{leftover}=15g

Regards!

6 0
3 years ago
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