Answer:
Mass of chemical = 1.5 mg
Explanation:
Step 1: First calculate the concentration of the stock solution required to make the final solution.
Using C1V1 = C2V2
C1 = concentration of the stock solution; V1 = volume of stock solution; C2 = concentration of final solution; V2 = volume of final solution
C1 = C2V2/V1
C1 = (6 * 25)/ 0.1
C1 = 1500 ng/μL = 1.5 μg/μL
Step 2: Mass of chemical added:
Mass of sample = concentration * volume
Concentration of stock = 1.5 μg/μL; volume of stock = 10 mL = 10^6 μL
Mass of stock = 1.5 μg/μL * 10^6 μL = 1.5 * 10^6 μg = 1.5 mg
Therefore, mass of sample = 1.5 mg
Answer:
Try quizlet, they have everything on there
Explanation:
B) Seawater. Because, it all has the same consistency. With the other choices, like vegetable soup, in one spoon full you may get a bit of potato but in another spoon full you may get a lima bean.
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Answer:
- C₃H₈ (g) + 5O₂(g) → 3CO₂ (g) + 4H₂O (l)
(option D. with the proviso that the subscripts of propane's chemical formula must be corrected)
Explanation:
<em>Propane</em> is the saturated hydrocarbon, alkane, with chemical formula C₃H₈ or CH₃CH₂CH₃.
The complete combustion of the hydrocarbons yield carbon dioxide (CO₂) and water (H₂O).
The chemical equation that represents this combustion is:
- C₃H₈ (g) + O₂(g) → CO₂ (g) + H₂O (l) (skeleton equation: unbalanced)
Once you balance it, you get:
- C₃H₈ (g) + 5O₂(g) → 3CO₂ (g) + 4H₂O (l)
Left side Right side
C 3 3
H 8 4×2 = 8
O 5×2 = 10 3×2 + 4 = 10
That equation corresponds to the option D. of the list, with the proviso that the subscripts of propane's chemical formula must be corrected
