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svlad2 [7]
2 years ago
7

Why are isotopes with short half-lives not useful for dating very old rocks?

Chemistry
2 answers:
kherson [118]2 years ago
5 0

Answer:

D

Explanation:

Very old rocks would be been formed before said isotopes with short half-lives. We're thinking of a very long geological time. The original rock might be rock C, then years and years later rock Y would be measured. Y can't match C since there's too much unknowns in between.

erma4kov [3.2K]2 years ago
4 0

Answer:

The radioactive isotopes within these brains typically record the ages of the grains-not the time when the sedimentary rock was formed, making it difficult to date using radiometric dating. The half-life of U-235 is 704 million years.

Explanation:

hope this helps but if i'm wrong then i'm sorry..

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What is exchanged between the system and the surroundings ​
BartSMP [9]

Answer:

see note under explanation

Explanation:

When describing system and surroundings the system is typically defined as the 'object of interest' being studied and surroundings 'everything else'. In thermodynamics heat flow is typically defined as endothermic or exothermic. However, one should realize that the terms endothermic and exothermic are in reference to the 'system' or object of interest being studied. For example if heat is transferred from a warm object to a cooler object it is imperative that the system be defined 1st. So, with that, assume the system is a warm metal cylinder being added into cooler water. When describing heat flow then the process is exothermic with respect to the metal cylinder (the system) but endothermic to the water and surroundings (everything else).

8 0
3 years ago
Does anyone know how to do this???
Bond [772]
Simply look at the periodic table and fill in what you know based on the table

The number of protons = atomic number
The number of electrons, Which is the same as the atomic number for atoms.

The number of valence electrons that is given by the group that the element is in, the top number of each column in the periodic table.







8 0
3 years ago
If the speed of a sound wave increases what other property of the wave must also increase when all other wave properties are hel
kati45 [8]
<h2>Frequency</h2>

Explanation:

Wave frequency is the number of waves that pass a fixed point in a given amount of time.

Wave speed is the speed at which a wave travels.

Let the wave speed be v

Let the wave frequency be f

Let the wave length be l

The wave speed,frequency and wave length are related by the equation v=f\times l.

When v increases,f increases on the other side to maintain equality when no other property is changing.

8 0
3 years ago
A buffered solution has a pH of 7.5. What would happen to the pH if a small
musickatia [10]

Answer:

Dear user,

Answer to your query is provided below

When small amount of acid was added to buffered solution, pH will change very less.

Explanation:

Buffer solution resists change in ph on adding small amount of acid or base but when we calculate the value of buffer capacity we take the change in ph when we add acid or base to 1 lit solution of buffer.This contradicts the definition of buffer solution.

5 0
3 years ago
Calculate the grams of sulfur dioxide, SO2, produced when a mixture of 35.0 g of carbon disulfide and 30.0 g of oxygen reacts. W
alekssr [168]

Answer:

58.9g of SO2 is produced

8g of oxygen remains unconsumed

Explanation:

The burning of Carbon disulfide (CS2) in oxygen. gives the reaction:

CS2 (g) + 3O2 (g) → CO2 (g) + 2SO2 (g)

Molar mass of CS2 = 76.139 g/mol

Molar mass of O2 = 15.99 g/mol

Molar mass of SO2 = 64.066 g/mol

Number of moles of CS2 = 35g/ 76.139 g/mol =0.46 moles

Number of moles of O2 = 30g/15.999 g/mol =1.88 moles

From the chemical reaction

1 mole of CS2 react with 3 moles of O2 to give 2 moles of SO2

Thus 0.46 moles of CS2 reacts to form 2× 0.46 = 0.92 moles of SO2

Mass of SO2 produced = 0.92×64.07 = 58.9g of SO2 is produced

thus 0.46 moles of CS2 reacts with 3 × 0.46 moles of O2 which is =1.38 moles of O2

Thus oxygen is the limiting reactant with 1.88 - 1.38 = 0.496~~0.5 mole remaining

Or 8g of oxygen

58.9g of SO2 is produced

oxygen is the limiting

4 0
3 years ago
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