All categories

3 years ago

There is free rotation about the carbons of ethane but not th

Chemistry

1 answer:

olya-2409 [2.1K]3 years ago

8 0

Answer:

C. the carbons in ethene are linked by double bonds

Explanation:

The reason for the lack of free rotation about the carbons of ethene is that they are linked with with double bonds.

In single bonds afforded with the ethane compound, there is free rotation.

The double bonds confer a special restriction on the rotational potential of the bonded atoms round the carbon.

You might be interested in

DAE

navik [9.2K]

Answer:

sample 3

Explanation:

i did this

6 0

3 years ago

Read 2 more answers

Read temprature on thermometer i am confusion

balu736 [363]

Answer:

a)22.2°C after adding magnesium

b)17.3°C before adding magnesium

c) 4.9 is change

8 0

3 years ago

A compound sample contains 60.87% c, 4.38% h, and 34.75% o by mass. it has a molar mass of 276.2 g/mol. what are the empirical a

Allushta [10]

Step 1) Assume we have 100 grams of the compound. Thus, we're starting with 60.87 grams C, 4.38 grams H, and 34.75 grams O.

Step 2) Convert the masses of each to moles.

60.87 grams C=5.068276436 mol C

4.38 grams H=4.345238095 mol H

34.75 grams O=2.171875 mol O

step 3) Determine your simplest whole-number ratio of moles by dividing each number of moles by the smallest number of moles. (In this case, the smallest number of moles is 2.171875 mol O)

O: $\frac{2.171875}{2.171875} = 1$

H: $\frac{4.345238095}{2.171875} = 2$

C: $\frac{5.068276436}{2.171875} = 2.33$

Step 4) Whenever you're doing an empirical formula problem, and you run into a number that ends with .33, rather than rounding down to a whole number, you need to multiply all your ratios by 3 to obtain whole numbers. Thus, you will get:

O=3

H=6

C=7

Step 5) write the empirical formula using the ratios.

The empirical formula is: C₇H₆O₃

Step 6) The subscripts in the molecular formula of a substance are always whole-number multiples of the subscripts in its empirical formula. This multiple is found by dividing the molecular weight (which was given to us in the problem: 276.2 amu) by the empirical formula weight (C₇H₆O₃ =138.118 amu).

$\frac{276.2}{138.118} = 2$

Step 7) simply multiply the subscripts in the empirical formula by the multiple, 2, and you will get the molecular formula.

The molecular formula is: C₁₄H₁₂O₆

6 0

3 years ago

It is the balance between thermal energy and intermolecular forces that determines the state of matter of any substance at room

ExtremeBDS [4]

Answer:

The correct option is;

2) Thermal energy increases by a factor of R

Explanation:

The equipartition energy theorem states that when molecules are in a state of thermal equilibrium, particles within the system posses equal average energy with each degree of freedom which can be known as energy due to a state of having a particular temperature or thermal energy given by the relation

$E_{th}$ = Kinetic energy of translation + Kinetic energy of rotation + Energy of vibration

For a mono-atomic gas, $E_{th}$ = 3/2·n·R·T

For a diatomic gas, $E_{th}$ = 5/2·n·R·T

For a solid element, $E_{th}$ = 3·n·R·T

Therefore, as the temperature is doubled, the thermal energy increases by a factor of R.

5 0

3 years ago

trans-2-Butene does not exhibit a signal in the double-bond region of the spectrum (1600–1850 cm-1); however, IR spectroscopy is

spayn [35]

Answer:

The other signal that would indicate the presence of a C= C bond appears close to 3100 $cm^{-1}$ .

Explanation:

Bands that appear above 3000 $cm^{-1}$ are often unsaturation diagnoses suggest. The band at 3000- 3100 $cm^{-1}$ is characteristics for C-H stretching frequencies and normally is overlaps with the ones for alkanes because it is a band of weak intensity.

4 0

3 years ago