Question

What will be the volume of a balloon at 98 kPa if its volume is 9.65 L at 235 kPa?

Answer 1

Boyle's Law or Boyle-Mariotte's Law: Under constant temperature, the volume occupied by a given fixed mass of a gas is inversely proportional to its pressure.

Formula:
$\frac{ P_{1} }{ P_{2} } = \frac{ V_{2} }{ V_{1} }$
Product of extremes equals product of means
$P_{1} * V_{1} = P_{2} * V_{2}$

Data:
$P_{1} = 235\:kPa$
$V_{1} = 9.65\:L$
$P_{2} = 98\:kPa$
$V_{2} = ?$

Solving:
$P_{1} * V_{1} = P_{2} * V_{2}$
$235*9.65 = 98*V_{2}$
$2267.75 = 98V_{2}$
$98V_{2} = 2267.75$
$V_{2} = \frac{2267.75}{235}$
$\boxed{\boxed{V_{2} \approx 23.14\:L}}\end{array}}\qquad\quad\checkmark$