A base produces hydroxide ion in water
PH of solution at 25ºC = 8.3
![[ H_3O^+] = 10 ^{-pH}](https://tex.z-dn.net/?f=%5B%20H_3O%5E%2B%5D%20%3D%2010%20%5E%7B-pH%7D%20)
![{H_3O^+] = 10 ^{-8.3}](https://tex.z-dn.net/?f=%7BH_3O%5E%2B%5D%20%3D%2010%20%5E%7B-8.3%7D)
![[H_3O^+] = 5.011*10^{-9} M](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%20%3D%205.011%2A10%5E%7B-9%7D%20%20M)
hope this helps!
Answer:
0.238 M
Explanation:
A 17.00 mL sample of the dilute solution was found to contain 0.220 M ClO₃⁻(aq). The concentration is an intensive property, so the concentration in the 52.00 mL is also 0.220 M ClO₃⁻(aq). We can find the initial concentration of ClO₃⁻ using the dilution rule.
C₁.V₁ = C₂.V₂
C₁ × 24.00 mL = 0.220 M × 52.00 mL
C₁ = 0.477 M
The concentration of Pb(ClO₃)₂ is:

To the right
Because there is an unbalanced force in that direction
:)