Answer: 10, 11, & 12
<u>Step-by-step explanation:</u>
Let x represent the age of the youngest child.
Their ages are consecutive so,
Youngest: x
Middle: x + 1
Oldest: x + 2
The age of the Youngest squared (x²) equals 8 times the Oldest [8(x + 2)] plus 4.
x² = 8(x + 2) + 4
x² = 8x + 16 + 4
x² = 8x + 20
x² - 8x - 20 = 0
(x - 10)(x + 2) = 0
x - 10 = 0 or x + 2 = 0
x = 10 or x = -2
Since age cannot be negative, x = -2 is not valid
So, the Youngest (x) is 10
the Middle (x + 1) is 11
and the Oldest (x + 2) is 12
B because it is between x: 4 and 6. And it is linear and decreasing
Answer:
- 1
Step-by-step explanation:
2x + 3 = x - 4
2x - x = - 4 + 3
x = - 1
The solution to the above equation is - 1.
Answer:0,3 for y and 4,0 for x
the second one is 0,6 for y and for the x it will be -3,0
Step-by-step explanation: