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raketka [301]
3 years ago
13

When a coin is tossed it is either heads or tails. Suppose heads has a point value of 1 and tails a point value of -1. if the su

m of the point value after 50 tosses is 14. How many of the tosses must have been heads?
Mathematics
1 answer:
zvonat [6]3 years ago
8 0

Answer:

32

Step-by-step explanation:

Totally there are 50 tosses.  

Let the number of tosses which resulted head be x.  

Therefore the number of tosses which resulted tail is 50−x.

We get x×1+(50−x)×(−1)=14

x−(50−x)=14

x−50+x=14

x=32

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