Question

When a coin is tossed it is either heads or tails. Suppose heads has a point value of 1 and tails a point value of -1. if the sum of the point value after 50 tosses is 14. How many of the tosses must have been heads?

Answer 1

Answer:

32

Step-by-step explanation:

Totally there are 50 tosses.  

Let the number of tosses which resulted head be x.  

Therefore the number of tosses which resulted tail is 50−x.

We get x×1+(50−x)×(−1)=14

x−(50−x)=14

x−50+x=14

x=32