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Sindrei [870]
3 years ago
5

How much work (in J) is involved in a chemical reaction if the volume decreases from 4.35 to 1.20 L against a constant pressure

of 0.822 atm?
Express your answer to three significant figures and include the appropriate units.
Chemistry
1 answer:
Marianna [84]3 years ago
3 0

Answer:

W = -262 J.

Explanation:

Hello there!

In this case, according to the given information, we can recall the definition of work in terms of constant pressure and variable volume as follows:

W=P(V_2-V_1)

So we plug in the given pressure and volumes to obtain:

W=0.822atm(1.20L-4.35L)\\\\W=-2.60atm*L

Now, we convert this number to J (Pa*m³) by using the shown below conversion factor:

W=-2.60atm*L*\frac{101325Pa}{1atm} *\frac{1m^3}{1000L}\\\\W=-262J

Regards!

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By Stoichiometry of the reaction:

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