Question

How much work (in J) is involved in a chemical reaction if the volume decreases from 4.35 to 1.20 L against a constant pressure of 0.822 atm?
Express your answer to three significant figures and include the appropriate units.

Answer 1

Answer:

W = -262 J.

Explanation:

Hello there!

In this case, according to the given information, we can recall the definition of work in terms of constant pressure and variable volume as follows:

$W=P(V_2-V_1)$

So we plug in the given pressure and volumes to obtain:

$W=0.822atm(1.20L-4.35L)\\\\W=-2.60atm*L$

Now, we convert this number to J (Pa*m³) by using the shown below conversion factor:

$W=-2.60atm*L*\frac{101325Pa}{1atm} *\frac{1m^3}{1000L}\\\\W=-262J$

Regards!