The three patters are clumped, random, and uniform
Hey there!
Molar mass NaCl = 58.44 g/mol
58.44 g ----------------- 22.4 ( at STP )
3.2 g -------------------- Volume ??
Volume = ( 3.2 x 22.4 ) / 58.44
Volume = 71.68 / 58.44
Volume = 1.226 L
Hope this helps!
Answer:
New volume V2 = 2.565 L
Explanation:
Given:
Old volume V1 = 10.8 L
Old pressure P1 = 0.38 atm
New presuure P2 = 1.6 atm
Find:
New volume V2
Computation:
P1V1 = P2V2
So,
10.8 x 0.38 = V2 x 1.6
New volume V2 = 2.565 L
percent by mass=(mass of solute/ mass of solution)*100 %
mass of solute=58.5 g
density (H₂O)=1 g/cm³*(1000 cm³/1dm³)=1000 g/dm³
mass of solvent (H₂O)=0.5 dm³ * (1000 g/dm³)=500 g
mass of solution=mass of solvent + mass of solut
mass of solution=58.5 g+500 g=558.5 g
% mass=(58.5 g/558.5 g) * 100%=10.47% of Na.
solution: 10.47% of Na.