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3 years ago

Help me please , what is the product of the following Substitution ?

Chemistry

1 answer:

Dovator [93]3 years ago

7 0

Answer:

Explanation:

I'm thinking,in this reaction, Na+ will took Br- away leaving carbocation at the site,there will be no arrangements cuz the double bond is not in localised!

so then ,O- will attach to the carbocation site to form B

I'M JUST NOT 100% SURE!!! ;()

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The pH of a solution is 8.83±0.048.83±0.04 . What is the concentration of H+H+ in the solution and its absolute uncertainty?

slava [35]

Answer:

The concentration of $H^{+}$ is 1.48 × $10^{-9}$ M

The absolute uncertainty of $[{H^{+}]$ is ±0.12 × $10^{-9}$ M

The concentration of $H^{+}$ is written as 1.48(±0.12) × $10^{-9}$ M

Explanation:

The pH of a solution is given by the formula below

pH = $-log_{10}[{H^{+}]$

∴ $[H^{+}] = 10^{-pH}$

where $[{H^{+}]$ is the $H^{+}$ concentration

From the question,

pH = 8.83±0.04

That is,

pH =8.83 and the uncertainty is ±0.04

First, we will determine $[{H^{+}]$ from

$[H^{+}] = 10^{-pH}$

$[{H^{+}] = 10^{-8.83}$

$[{H^{+}] = 1.4791$ × $10^{-9}$ M

$[{H^{+}] = 1.48$ × $10^{-9}$ M

The concentration of $H^{+}$ is 1.48 × $10^{-9}$ M

The uncertainty of $[{H^{+}]$ ( $U_{[H^{+}] }$ ) from the equation $[H^{+}] = 10^{-pH}$ is

$U_{[H^{+}] } = 2.303 \\$ × ${[H^{+}] }$ × $U_{pH }$

Where $U_{[H^{+}] }$ is the uncertainty of $[{H^{+}]$

$U_{pH }$ is the uncertainty of the pH

Hence,

$U_{[H^{+}] }$ = 2.303 × 1.4791 × $10^{-9}$ × 0.04

$U_{[H^{+}] }$ = 1.36 × $10^{-10}$ M

$U_{[H^{+}] }$ = 0.12 × $10^{-9}$ M

Hence, the absolute uncertainty of $[{H^{+}]$ is ±0.12 × $10^{-9}$ M

6 0

4 years ago

The most common source of copper (Cu) is the mineral chalcopyrite (CuFeS2). How many kilograms of chalcopyrite must be mined to

diamong [38]

Answer:

0.693kg of CuFeS2 is needed to produce 240 grams of Cu.

Explanation:

In 1 mole of CuFeS2 is associated 1 mole of Cu.

Molar mass of CuFeS2 = 183.5 g/mol

Molar mass of Cu = 63.5g/mol

No of moles of copper present in 240g of chalcopyrite = 240/63.5 = 3.779moles

we know

1 mole of Cu → 1 mole of CuFeS2

in 3.779 moles of Cu → 3.779 moles of CuFeS2

3.779 moles of CuFeS2 = 3.779 * 183.5 = 693.45grams

CuFeS2 in kg = 0.693kg

5 0

3 years ago

Determine the value of the equilibrium constant for the following reaction, where the following amounts of each species are pres

dezoksy [38]

Explanation:

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3 years ago

Will Mark Brainlest ( all the disaster are hazard but all the hazard are not disaster) give reason

Svetlanka [38]

Answer:

Explanation to the following question is as follows;

Explanation:

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3 years ago

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A fault is a break in the rocks of the Earth's crust. A fault is formed due to the movement of rock on either side of the fault.

SVEN [57.7K]

Answer:

Ola tudo bem??

Meu nome é Ana Kesia, e o seu?

Foi mal, Nn consegui responder sua pergunta!

Mais mesmo assim obrigada pelos pontos!

Qualquer dúvidas estou aqui para ajudar!

Boa tarde, Tchau.

4 0

3 years ago