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Rzqust [24]
3 years ago
12

Select the correct answer. What is the value of this expression when g= -3.5? 8-[2g-5]

Mathematics
1 answer:
Aleks [24]3 years ago
6 0

Answer:

20

Step-by-step explanation:

2g =  -3.5x2 = -7

-7 - 5= -12

8 - -12=20

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The scale on a map of Virginia shows that 1 inch represents 15 miles. The actual distance from Richmond, VA, to Washington, D.C.
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Answer:

The answer to your question is: 7 1/3 inches

Step-by-step explanation:

Data

1 inch --------- 15 miles

Distance from Richmond to Washington = 110 miles

Use a rule of three to solve it

        1 inch ----------------- 15 miles

        x    --------------------  110 miles

x = 110x 1 /15

x = 110 / 15   simplify            dividing by 5

x = 22/3

Convert it to a mix number

22/3 = 7 1/3 inches

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In an election between two candidates, the winner received 65% of the 15,000 votes. The loser received the remaining votes. How
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Answer:The winner recieved 4,500 more votes than the loser

Step-by-step explanation:

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(5x – 4y) (7x2 – 12x + 27)
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205x-60x^2-164y+48xy

Step-by-step explanation:

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Assume that there are an equal number of births in each month so that the probability is that a person chosen at random was born
NikAS [45]

Answer:

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have a birthday in May, or they do not. The probability of a person having a birthday in May is independent of any other person. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of a person being in May:

May has 31 days in a year of 365. So

p = \frac{31}{365} = 0.0849

Group of 20 friends:

This means that n = 20

What is the probability that at the May celebration, exactly two members of the group have May birthdays?

This is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{20,2}.(0.0849)^{2}.(0.9151)^{18} = 0.2773

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

3 0
3 years ago
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