Answer : The initial volume was, 71.2 mL
Explanation :
To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.
The equation follows:

where,
are the initial pressure, volume and temperature of the gas
are the final pressure, volume and temperature of the gas
We are given:
![P_1=0.85atm\\V_1=?\\T_1=66^oC=[66+273]K=339K\\P_2=0.60atm\\V_2=94mL\\T_2=43^oC=[43+273]K=316K](https://tex.z-dn.net/?f=P_1%3D0.85atm%5C%5CV_1%3D%3F%5C%5CT_1%3D66%5EoC%3D%5B66%2B273%5DK%3D339K%5C%5CP_2%3D0.60atm%5C%5CV_2%3D94mL%5C%5CT_2%3D43%5EoC%3D%5B43%2B273%5DK%3D316K)
Now put all the given values in above equation, we get:


Therefore, the initial volume was, 71.2 mL
Since you're only asking for the last 3 items, here are the answers:
3. Maine is located in the northern hemisphere. If there is a high pressure, the wind is blowing clockwise. If there is a low pressure, the wind direction will be in the opposite direction.
4. Colorado is in the northern hemisphere. If there is a low pressure, the wind is going counterclockwise. If there is a high pressure, the opposite is true.
5. There is no map so I can't give you the exact answers.
Here, we are going to calculate the mass % of C in the mixture.
What is a Mixture?
A mixture is composed of one or more pure substances in varying composition. There are two types of mixtures: heterogeneous and homogeneous. Heterogeneous mixtures have visually distinguishable components, while homogeneous mixtures appear uniform throughout.
Given that,
The mass % of CO =35.0% =35.0 g in 100 g mixture
The mass % of CO2 = 65% =65 g in 100 g mixture
Therefore,
The mass of C from CO = 15.007 g C
Similarly,
The mass of C from CO2 = 17.738 g C
Thus, the total mass of C = 15.007 g+17.738 g =32.745 g
Therefore,
The mass % of C= 32.745% =32.7%
Thus, the mass % of C in the mixture is 32.7%
To learn more about carbon-containing compounds click on the link below:
brainly.com/question/13381262
#SPJ4
Answer:
It will require<u> second round</u> of the cycle to release 
Explanation:
<u>Reason behind the requirement of second round of the cycle to release </u>
-:
The C4 carbon of succinyl CoA is acetyl from acetyl CoA. Succinyl CoA is converted to succinate, which is then converted to fumarate, fumarate, malate, and eventually oxaloacetate. 14C will be found in oxaloacetate at either C1 or C4. During the second round of the loop, each of these carbons will be converted to carbon dioxide.
Answer:
Explanation:
Flame test:
The metals ions can be detected through the flame test. Different ions gives different colors when heated on flame. Tom perform the flame test following steps should follow:
1. Dip a wire loop in the solution of compound which is going to be tested.
2. After dipping put the loop of wire on bunsen burner flame.
3. Observe the color of flame.
4. Record the flame color produce by compound
Color produce by metals:
Red = Lithium, zirconium, strontium, mercury, Rubidium (red violet)
Orange-red = calcium
Yellow = sodium, iron (brownish yellow)
Green = green
Blue = cesium. arsenic, copper, tantalum, indium, lead
Violet = potassium (lilac)