The solids are characterized as amorphous and crystalline solids based on the arrangement of atoms. The solids that are amorphous are rubber, plastic, candle wax, and glass.
<h3>What are amorphous solids?</h3>
The solids have the arrangement of atoms in the lattice. The solids with an appropriate arrangement of atoms are crystalline solids. For example, sugar, graphite.
The solids with irregular arrangements of atoms in the lattice are amorphous solids. For example, glass, rubber.
Thus, the solids that are amorphous in nature are rubber, plastic, candle wax, and glass.
Learn more about amorphous solids, here:
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Answer:
An atom is a particle of matter that uniquely defines achemical element. An atom consists of a central nucleus that is usually surrounded by one or more electrons. ... The nucleus is positively charged, and contains one or more relatively heavy particles known as protons and neutrons.
Based on the calculations, the approximate ductility (%el) of this brass is equal to 2.3%.
<u>Given the following data:</u>
- Yield strength = 230 mpa (33360 psi).
<h3>What is ductility?</h3>
Ductility can be defined as an important property of a material which determines its ability to become elongated due to the application of stress.
Mathematically, the ductility of a material can be expressed as percentage elongation in length:
<u>Where:</u>
is the original length.
is the final length.
is the yield strength.
For this exercise, let us assume the original length of this brass is equal to 100 meters.
Substituting the parameters into the formula, we have;
Ductility = 2.3%.
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Answer:
Kc = Kc = 8.0 * 10^9
Kp = 5.5 *10^5
Explanation:
Step 1: Data given
Temperature = 25.0 °C
Number of moles Fe = 1.0 moles
Number of moles O2 = 1.0 * 10^-3 moles
Number of moles Fe2O3 = 2.0 moles
Volume = 2.0 L
Step 2: The balanced equation
4Fe(s) + 3O2(g) ⇌ 2Fe2O3(s)
Step 3: Calculate molarity
Molarity = moles / volume
[Fe] = 1.0 moles / 2.0 L
[Fe] = 0.5 M
[O2] = 0.001 moles / 2.0 L
[O2] = 0.0005 M
[Fe2O3] = 2.0 moles / 2.0 L
[Fe2O3] = 1.0 M
Step 4: Calculate Kc
Kc =1/ [O2]³
Kc = 1/0,.000000000125
Kc = 8.0 * 10^9
Step 5: Calculate Kp
Kp = Kc*(R*T)^Δn
⇒with Kc = 8.0*10^9
⇒with R = 0.08206 L*atm /mol*K
⇒with T = 298 K
⇒with Δn = -3
Kp = 8.10^9 *(0.08206 * 298)^-3
Kp = 5.5 *10^5
Answer:
it has to be a no cap !! buh
