The piano strings<span> for </span>low notes<span> are heavier, </span>have<span> more inertia, and </span>vibrate<span> at a lower frequency a lower pitch than lighter </span>strings<span> of the same </span>string<span> tension. Loudness involves how hard the keys are struck, which affects the amplitudes of the </span>vibrating strings<span>. the touch sensitivity of the </span>piano<span> distinguishes it from earlier.
Do you undertand?????
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Answer:
An asteroid that has an orbital period of 3 years will have an orbital with a semi-major axis of about 2 years.
Explanation:
Given;
orbital period of 3 years, P = 3 years
To calculate the years of an orbital with a semi-major axis, we apply Kepler's third law.
Kepler's third law;
P² = a³
where;
P is the orbital period
a is the orbital semi-major axis
(3)² = a³
9 = a³
a = ![a = \sqrt[3]{9} \\\\a = 2.08 \ years](https://tex.z-dn.net/?f=a%20%3D%20%5Csqrt%5B3%5D%7B9%7D%20%5C%5C%5C%5Ca%20%3D%202.08%20%5C%20years)
Therefore, An asteroid that has an orbital period of 3 years will have an orbital with a semi-major axis of about 2 years.
Answer:

Explanation:
Given that,
The uncertainty in the position of an electron along the x-axis is, 
We need to find the east uncertainty in any simultaneous measurement of the momentum component of this electron.
We know that the Heisenberg's uncertainty principle gives the relation between the uncertainty in position and the momentum of electron as :

Putting all the values, we get :

So, the momentum component of this electrons is greater than
.
<span>the Steady State Theory is the answer to this I believe!</span>