Answer: By moving heat from the equator toward the poles, ocean currents play an important role in controlling the climate. Ocean currents are also critically important to sea life.
Explanation: Plzz mark me as brainliest !!
Answer:
The dimension is 
Explanation:
From the question we are told that

Here ![[J] = \frac{1}{L^2 T}](https://tex.z-dn.net/?f=%5BJ%5D%20%3D%20%5Cfrac%7B1%7D%7BL%5E2%20T%7D)
![[n] =\frac{1}{L^3}](https://tex.z-dn.net/?f=%5Bn%5D%20%3D%5Cfrac%7B1%7D%7BL%5E3%7D)
![[x] = L](https://tex.z-dn.net/?f=%5Bx%5D%20%3D%20L)
So
![\frac{1}{L^2 T} = -D \frac{d(\frac{1}{L^3})}{d[L]}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BL%5E2%20T%7D%20%3D%20%20-D%20%5Cfrac%7Bd%28%5Cfrac%7B1%7D%7BL%5E3%7D%29%7D%7Bd%5BL%5D%7D)
Given that the dimension represent the unites of n and x then the differential will not effect on them
So
=> 
=> 
Answer:
hope this helps!
Explanation:
Volume of the air bubble, V1=1.0cm3=1.0×10−6m3
Bubble rises to height, d=40m
Temperature at a depth of 40 m, T1=12oC=285K
Temperature at the surface of the lake, T2=35oC=308K
The pressure on the surface of the lake: P2=1atm=1×1.103×105Pa
The pressure at the depth of 40 m: P1=1atm+dρg
Where,
ρ is the density of water =103kg/m3
g is the acceleration due to gravity =9.8m/s2
∴P1=1.103×105+40×103×9.8=493300Pa
We have T1P1V1=T2P2V2
Where, V2 is the volume of the air bubble when it reaches the surface.
V2=
I think is c not sure though
A tsunami.........................................................................................................