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3 years ago

Which one of the following compounds is not covalent?

Chemistry

2 answers:

denpristay [2]3 years ago

8 0

Answer:

KCl

Explanation:

Hello,

Potassium chloride is well-known as an ionic compound owing to the shown-below greater-than-1.7 difference between the electronegativities of potassium and chlorine:

$\Delta E=E_{Cl}-E_K=3.16-0.82\\\Delta E=2.34$

This is by cause of the fact that such compounds that have a difference in the constituent elements' electronegativities greater than 1.7 are considered as ionic.

Best regards.

denpristay [2]3 years ago

5 0

KCI is not a covalent compound, it is an ionic compound.
A covalent compound is one in which each of the atoms involved contribute a specific number of electrons for sharing in order to from stable compound while an ionic compound is a compound formed when one atom donates electron to the other atom in the compound, in order to attain stability. The compounds given in options A, B and D shared electrons while in KCl, potassium donates an electron to chlorine.

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Explanation:

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3 years ago

Compound X has a molar mass of 283.89 mol^-1 and the following composition:

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3 years ago

You can prepare a buffer solution by combining equal moles of which pair of substances?

zzz [600]

Answer:

A. weak acid and its conjugate base

Explanation:

A buffer solution can be made with a weak acid and conjugate base or a weak base and conjugate acid.

This may help you:

https://chem.libretexts.org/Bookshelves/Physical_and_Theoretical_Chemistry_Textbook_Maps/Supplemental_Modules_(Physical_and_Theoretical_Chemistry)/Acids_and_Bases/Buffers/Introduction_to_Buffers

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3 years ago

Hydroxylamine hydrochloride is a powerful reducing agent which is used as a polymerization catalyst. It contains 5.80 mass % H,

ludmilkaskok [199]

Answer: The empirical formula for the given compound is $H_{4}O_1N_1Cl_1=H_4NOCl$

Explanation:

We are given:

Percentage of H = 5.80 %

Percentage of O = 23.02 %

Percentage of N = 20.16 %

Percentage of Cl = 51.02 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of H = 5.80 g

Mass of O = 23.02 g

Mass of N = 20.16 g

Mass of Cl = 51.02 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{5.80g}{1g/mole}=5.80moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{23.02g}{16g/mole}=1.44moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{20.16g}{14g/mole}=1.44moles$

Moles of Chlorine = $\frac{\text{Given mass of Chlorine}}{\text{Molar mass of Chlorine}}=\frac{51.02g}{35.5g/mole}=1.44moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 1.44 moles.

For Hydrogen = $\frac{5.80}{1.44}=4.03\approx 4$

For Oxygen = $\frac{1.44}{1.44}=1$

For Nitrogen = $\frac{1.44}{1.44}=1$

For Chlorine = $\frac{1.44}{1.44}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of H : O : N : Cl = 4 : 1 : 1 : 1

Hence, the empirical formula for the given compound is $H_{4}O_1N_1Cl_1=H_4NOCl$

3 0

3 years ago

To measure the amount of chlorine in a well-boring fluid, an analytical chemist adds silver nitrate solution to a sample of the

anyanavicka [17]

Answer:

c. precipitation

Explanation:

Let's consider the following balanced net ionic equation.

Cl⁻(aq) + AgNO₃(ag) ⇒ AgCl(s) + NO₃⁻ (ag)

What kind of reaction is this?

a. acid-base. No, because the reactants are not acids and bases.

b. redox. No, because all the species have the same oxidation numbers in the reactants and the products

c. precipitation. Yes, because an insoluble compound (AgCl) is produced, which then precipitates.

3 0

3 years ago