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velikii [3]
3 years ago
10

Which one of the following compounds is not covalent?

Chemistry
2 answers:
denpristay [2]3 years ago
8 0

Answer:

KCl

Explanation:

Hello,

Potassium chloride is well-known as an ionic compound owing to the shown-below greater-than-1.7 difference between the electronegativities of potassium and chlorine:

\Delta E=E_{Cl}-E_K=3.16-0.82\\\Delta E=2.34

This is by cause of the fact that such compounds that have a difference in the constituent elements' electronegativities greater than 1.7 are considered as ionic.

Best regards.

denpristay [2]3 years ago
5 0
KCI is not a covalent compound, it is an ionic compound. 
A covalent compound is one in which each of the atoms involved contribute a specific number of electrons for sharing in order to from stable compound while an ionic compound is a compound formed when one atom donates electron to the other atom in the compound, in order to attain stability.  The compounds given in options A, B and D shared electrons while in KCl, potassium donates an electron to chlorine.
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Scientist can use the of minerals to tell them apart A.sound B.length C.size D.color
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Answer:

color

Explanation:

Scientists can use the color of minerals to tell them apart.

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A ball is dropped from a height of 20 meters. At what height does the ball have a velocity of 10 meters/second?
musickatia [10]

Answer:

15m

Explanation:

vi = 0

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10^2 = 0 + 2(-9.8)(x2-x1) = -5.1

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2 years ago
If 12.5 grams of strontium hydroxide is reacted with 150 mL of 3.5 M carbonic acid, identify the limiting reactant.
kiruha [24]

Answer:

Sr(OH)₂ will be the limiting reagent.

Explanation:

First of all, you should know the following balanced chemical equation:

2 H₂CO₃ + 2 Sr(OH)₂ → 4 H₂O + Sr₂(CO₃)₂

The balanced equation is based on the Law of Conservation of Mass, which says that matter cannot be created or destroyed. Therefore, the number of each type of atom on each side of a chemical equation must be the same.      

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use the reaction stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction). By stoichiometry the following amounts in moles react:

  • strontium hydroxide: 2 moles
  • carbonic acid: 2 moles

Now, you know the following masses of the elements:

  • Sr: 87.62 g/mole
  • O: 16 g/mole
  • H: 1 g/mole

So the molar mass of strontium hydroxide is:

Sr(OH)₂= 87.62 g/mole + 2*(16 g/mole + 1 g/mole)= 121.62 g/mole

You apply the following rule of three, if 121.62 grams of hydroxide are present in 1 mole, 12.5 grams in how many moles are they?

moles of strontium hydroxide=\frac{12.5 grams*1 mole}{121.62 grams}

moles of hydroxide= 0.103 moles

On the other hand, you have 150 ml of 3.5 M carbonic acid. Since molarity is the concentration of a solution expressed in the number of moles dissolved per liter of solution, you can apply the following rule of three: if in 1 L there are 3.5 moles of carbonic acid, in 0.150 L (being 1 L = 1000 mL, 0.150 L = 150 mL) how many moles of acid are there?

molesofcarbonicacid=\frac{0.150 L*3.5 moles}{1 L}

moles of carbonic acid= 0.525 moles

Finally, to calculate the limiting reagent, you can use a simple rule of three as follows: if by stoichiometry 2 mole of strontium hydroxide reacts with , how much moles of carbonic acid will be needed if 0.103 moles of strontium hydroxide react?

molesofcarbonicacid=\frac{0.103 moles of strontium hydroxide*2 moles of carbonic acid}{2 moles of strontium hydroxide}

moles of carbonic acid= 0.103 moles

But 0.525 moles are available. Since more moles are available than you need to react with 0.103 moles of strontium hydroxide, <u><em>Sr(OH)₂ will be the limiting reagent.</em></u>

7 0
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Eva8 [605]
The balanced chemical reaction is:

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We are given the amount of sodium to be used up in the reaction. This will be the starting point for our calculations.

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marusya05 [52]

Answer:

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