The question ask for the percentage of the abundance of galium-69 where there is two isotopes of galium: the 69Ga and the 71Ga. The average atomic mass of gallium is 69.723 amu. So the formula would be <span>69.723amu=(%x)∗(68.926amu)+(1−%x)∗(70.025amu) and the answer to this is 1.58%</span>
I believe the answer is 65.254%
Number of moles ( substance x ):
1 mole --------- 58.45 g/mol
? mole --------- 326.0 g
326.0 x 1 / 58.45 => 5.577 moles
heat of fusion:
hf = Cal / moles
hf = 4325.8 Cal / 5.577 moles
hf = 775.65 cal/mol
hope this helps!
Answer:
i think d maybe correct me if im wrong
Explanation:
The answer is 80 m.
Centripetal force (F) is a force that makes body move around a circular curve. The unit of force is N (N = kg * m/s²).
It can be represented as:

where:
m - mass
v - velocity
r - radius of the curve
We have:
m = 1,200 kg
V = 20 m/s
F = 6,000 N = 6,000 kg * m/s²
We need radius of the curve:
r = ?
So, if <span>

, then:
</span>

⇒

⇒

⇒

⇒