This is sort of simple. 2 grams of X can combine with 4 grams of Y to form XY. Y is 2 times the amount of grams in X. So if there are 11 grams of X there are 22 grams of Y to form XY. Or you could take 11 divided by 2 is 5.5 and then multiply 4 by 5.5 to get 22. If this is wrong please tell me I would be very happy to know.
Answer:
5.15348 Beats/s
4.55 mm
Explanation:
= Velocity of sound = 342 m/s
= Velocity of sound = 346 m/s
= First frequency = 440 Hz
Frequency is given by
![f_2=\frac{v_2}{2L_1}\\\Rightarrow f_2=\frac{346}{2\times 0.38863}\\\Rightarrow f_2=445.15348\ Hz](https://tex.z-dn.net/?f=f_2%3D%5Cfrac%7Bv_2%7D%7B2L_1%7D%5C%5C%5CRightarrow%20f_2%3D%5Cfrac%7B346%7D%7B2%5Ctimes%200.38863%7D%5C%5C%5CRightarrow%20f_2%3D445.15348%5C%20Hz)
Beat frequency is given by
![|f_1-f_2|=|440-445.15348|=5.15348\ Beats/s](https://tex.z-dn.net/?f=%7Cf_1-f_2%7C%3D%7C440-445.15348%7C%3D5.15348%5C%20Beats%2Fs)
Beat frequency is 5.15348 Hz
Wavelength is given by
![\lambda_1=\frac{v_1}{f}\\\Rightarrow \lambda_1=\frac{342}{440}\\\Rightarrow \lambda_1=0.77727\ m](https://tex.z-dn.net/?f=%5Clambda_1%3D%5Cfrac%7Bv_1%7D%7Bf%7D%5C%5C%5CRightarrow%20%5Clambda_1%3D%5Cfrac%7B342%7D%7B440%7D%5C%5C%5CRightarrow%20%5Clambda_1%3D0.77727%5C%20m)
Relation between length of the flute and wavelength is
![\lambda_1=2L_1\\\Rightarrow L_1=\frac{\lambda_1}{2}\\\Rightarrow L_1=\frac{0.77727}{2}\\\Rightarrow L_1=0.38863\ m](https://tex.z-dn.net/?f=%5Clambda_1%3D2L_1%5C%5C%5CRightarrow%20L_1%3D%5Cfrac%7B%5Clambda_1%7D%7B2%7D%5C%5C%5CRightarrow%20L_1%3D%5Cfrac%7B0.77727%7D%7B2%7D%5C%5C%5CRightarrow%20L_1%3D0.38863%5C%20m)
At v = 346 m/s
![\lambda_2=\frac{v_2}{f}\\\Rightarrow \lambda_2=\frac{346}{440}\\\Rightarrow \lambda_1=0.78636\ m](https://tex.z-dn.net/?f=%5Clambda_2%3D%5Cfrac%7Bv_2%7D%7Bf%7D%5C%5C%5CRightarrow%20%5Clambda_2%3D%5Cfrac%7B346%7D%7B440%7D%5C%5C%5CRightarrow%20%5Clambda_1%3D0.78636%5C%20m)
![L_2=\frac{\lambda_2}{2}\\\Rightarrow L_2=\frac{0.78636}{2}\\\Rightarrow L_2=0.39318\ m](https://tex.z-dn.net/?f=L_2%3D%5Cfrac%7B%5Clambda_2%7D%7B2%7D%5C%5C%5CRightarrow%20L_2%3D%5Cfrac%7B0.78636%7D%7B2%7D%5C%5C%5CRightarrow%20L_2%3D0.39318%5C%20m)
Difference in length is
![\Delta L=L_2-L_1\\\Rightarrow \Delta L=0.39318-0.38863\\\Rightarrow \Delta L=0.00455\ m=4.55\ mm](https://tex.z-dn.net/?f=%5CDelta%20L%3DL_2-L_1%5C%5C%5CRightarrow%20%5CDelta%20L%3D0.39318-0.38863%5C%5C%5CRightarrow%20%5CDelta%20L%3D0.00455%5C%20m%3D4.55%5C%20mm)
It extends to 4.55 mm
Answer:
it is sooo easy u need to use magnetic panels on the rail and put the magnet on the train it works under the principal of magnetic
To solve this we assume
that the gas inside is an ideal gas. Then, we can use the ideal gas
equation which is expressed as PV = nRT. At a constant pressure and number of
moles of the gas the ratio T/V is equal to some constant. At another set of
condition of temperature, the constant is still the same. Calculations are as
follows:
T1 / V1 = T2 / V2
V2 = T2 x V1 / T1
V2 = 659.7 x 28 / 504.7
<span>V2 = 36.60 in^3</span>