Answer:
The change in internal energy of the system is -17746.78 J
Explanation:
Given that,
Pressure
Remove heat
Radius = 0.272 m
Distance d = 0.163 m
We need to calculate the internal energy
Using thermodynamics first equation
...(I)
Where, dU = internal energy
Q = heat
W = work done
Put the value of W in equation (I)
Where, W = PdV
Put the value in the equation
Hence, The change in internal energy of the system is -17746.78 J
