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ruslelena [56]
3 years ago
9

Carl went on a Euro Trip and was traveling from Spain to Russia. When he looked on the map it said Russia was 7035 km away from

Spain. If it took Carl 7 hours to get there, what would his average speed be in meters per second?
Physics
1 answer:
bija089 [108]3 years ago
3 0

Answer:

The average speed would be 279.167 meters per second.

Explanation:

Speed ​​is the magnitude that expresses the variation in position of an object and as a function of time. In other words, speed is defined as the relationship established between the distance traveled and the time elapsed in the movement of a mobile.

Speed can be calculated using the following expression:

Speed=\frac{distance}{time}

In this case:

  • distance= 7,035 km
  • time= 7 hours

Since the required unit of speed is meter per second, then you convert from km to meters for the case of distance, and from hours to seconds for the case of time. So:

  • distance= 7,035 km= 7,035,000 m (being 1 km= 1,000 m)
  • time= 7 hours= 420 minutes= 25,200 seconds (being 1 hour=60 minutes and 1 minute=60 seconds)

Replacing in the definition of speed:

Speed=\frac{7,035,000 meters}{25,200 seconds}

Solving:

Speed=279.167\frac{meters}{ seconds}

Then, <u><em>the average speed would be 279.167 meters per second.</em></u>

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During electrical storms, a bolt of lightning can transfer 10 C of charge in 2.0 µs (the amount of time can vary considerably).
nydimaria [60]

Answer:

Explanation:

charge, q = 10 C

time, t = 2 micro second

Current, i = q / t

i = 10 / (2 x 10^-6) = 5 x 10^6 A

(a)

distance, d = 1 m

the formula for the magnetic field is given by

B = \frac{\mu_{0}}{4\pi}\frac{2i}{d}

B = 10^{-7}\frac{2\times 5\times 10^{6}}{1}

B = 1 Tesla

Now the distance is d' = 1 km = 1000 m

B' = \frac{\mu_{0}}{4\pi}\frac{2i}{d}

B' = 10^{-7}\frac{2\times 5\times 10^{6}}{1000}

B' = 0.001 Tesla

(b) The magnetic field of earth is Bo = 3 x 10^-5 tesla

B / Bo = 3.3 x 10^4

B'/Bo = 33.3

4 0
3 years ago
In the sport of parasailing, a person is attached to a rope being pulled by a boat while hanging from a parachute-like sail. A r
IrinaK [193]

Answer:

570 N

Explanation:

Draw a free body diagram on the rider.  There are three forces: tension force 15° below the horizontal, drag force 30° above the horizontal, and weight downwards.

The rider is moving at constant speed, so acceleration is 0.

Sum of the forces in the x direction:

∑F = ma

F cos 30° - T cos 15° = 0

F = T cos 15° / cos 30°

Sum of the forces in the y direction:

∑F = ma

F sin 30° - W - T sin 15° = 0

W = F sin 30° - T sin 15°

Substituting:

W = (T cos 15° / cos 30°) sin 30° - T sin 15°

W = T cos 15° tan 30° - T sin 15°

W = T (cos 15° tan 30° - sin 15°)

Given T = 1900 N:

W = 1900 (cos 15° tan 30° - sin 15°)

W = 570 N

The rider weighs 570 N (which is about the same as 130 lb).

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3 years ago
How do resistors in parallel affect the total resistance?
4vir4ik [10]

Answer:

They're going to increase the total resistance as R_{T} = \sum\limits_{i=1}^N \left(\frac{1}{R_i} \right)^{-1}

Explanation:

If the resistors are in parallel, the potential difference is the same for each resistor. But the total current is the sum of the currents that pass through each of the resistors. Then

I = I_1 + I_2 + ... + I_N

where

I_i = \frac{V_i}{R_i}

but

V_i = V_j = V for i,j= 1, 2,..., N

so

I = \frac{V}{R_1}+ \frac{V}{R_2} + ... + \frac{V}{R_N} = \left(\frac{1}{R_1} +\frac{1}{R_2} + ... + \frac{1}{R_N}\right)V = \frac{V}{R_T}

where

R_T = \left(\frac{1}{R_1} +\frac{1}{R_2} + ... + \frac{1}{R_N}\right)^{-1} =\sum\limits_{i=1}^N \left(\frac{1}{R_i} \right)^{-1}

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It is weight, if I understand your question.
4 0
3 years ago
A light with a second-order bright band forms a diffraction angle of 30.0°. The diffraction grating has 250.0 lines per mm. What
Simora [160]
I have no idea sorry
7 0
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