Answer:
the final potential energy of this system is 3U0/10
Explanation:
We are given
charge at left end and another test charge at point p
Potential energy is given by = 
where k is electrostatics constant = 
Q1 = first charge , Q2= test charge
R= distance between charges
potential at point p
U0 = k*Q1*Q2 /3 ⇒ kq1q2 = 3U0 ..............1
now the test charge moves to point R
using Pytahgoreou theorem
R(distance) = 
= 10
New Potential energy
U1 = kq1*q2 / 10
substituting kq1q2 = 3U0 from 1
U1 = 3U0/10
So this is the final potential energy of this system.
Answer:
d = 0.076 mm
Explanation:
Given data
diffraction pattern d1 = 0.19 mm = 0.019 cm
separated s(1) = 1.8 cm
separated s(2) = 4.5 cm
to find out
d2 for an unknown
solution
we know here that spacing in between the diffraction fringe is always inversely proportional to diffraction grating so
we will apply here formula for unknown d that is
d1 (s1 / L) = d2 (s2 /L)
d2 = d1 × s(1) / s(2)
put here all thes evalue we get d2
d2 = d1 × s(1) / s(2)
d2 = 0.019 × 1.8 / 4.5
d2 = 0.0076 cm
d2 = 0.076 mm
Bro the picture is too dark I can’t see do it again so I can help you
Explanation:
The Coulomb's law states that the magnitude of each of the electric forces between two point-at-rest charges is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:
In this case we have an electron (-e) and a proton (e), so:
In this case, the electric force is negative, therefore, the force is repulsive and its magnitude is:
