Which equation is equivalent to Log (26•35) ?

Which of the following does Archimedes' principle help to explain?

irina1246 [14]

Which of the following does Archimedes' principle help to explains

O

C. Surface tension

6 0

3 years ago

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A hiker leaves her camp and walks 3.5 km in a direction of 55° south of west to the lake. after a short rest at the lake, she hi

3241004551 [841]

Let's choose east as positive x-direction and south as positive y-direction. We can resolve the two displacement along these two axes:

- Displacement 1 (3.5 km, $55^{\circ}$ south of west

$d_{1x}=-(3.5 km)( cos 55^{\circ})=-2.01 km$

$d_{1y}=(3.5 km)( sin 55^{\circ})=2.87 km$

- Displacement 2 (2.7 km, $16^{\circ}$ east of south

$d_{2x}=(2.7 km)( sin 16^{\circ})=0.74 km$

$d_{1y}=(2.7 km)( cos 16^{\circ})=2.60 km$

So, the total components on the two directions are

$d_x = -2.01 km+0.74 km=-1.27 km$

$d_y=2.87 km+2.60 km=5.47 km$

And the magnitude of the hiker's resultant displacement is

$d=\sqrt{(1.27 km)^2+(5.47 km)^2}=5.6 km$

8 0

3 years ago

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If a force of 50 n stretches a spring 0.10 m, what is the spring constant?

Oksanka [162]

Kx = F
k * 0.1 = 50
k = 50/0.1 = 500 N/m

6 0

4 years ago

A compound wall consists of parallel layers of two different materials, 10 cm of brick and 2 cm of wood. If the difference of te

RSB [31]

The temperature difference between the wooden wall is 16⁰C, and the heat current per square metre of the wall is 7,325 W/m².

<h3>Temperature difference between the wooden wall</h3>

The temperature difference between the wooden wall is calculated as follows;

Let the brick wall = wall A
Let the wooden wall = wall B
Let the area of the walls = A

$\frac{dQ_A}{dt } = \frac{dQ_B}{dt} \\\\\frac{K_A \Delta T_A \times A}{L_A} = \frac{K_B \Delta T _B \times A}{L_B}\\\\\frac{K_A \Delta T_A }{L_A} = \frac{K_B \Delta T _B}{L_B}\\\\\frac{0.5 \times 20}{0.1} = \frac{0.125 \times \Delta T _B }{0.02} \\\\100 = 6.25\Delta T _B\\\\\Delta T _B = \frac{100}{6.25} \\\\\Delta T _B = 16 \ ^oC$

<h3 /><h3>Heat flowing in the walls</h3>

Q = KL(ΔT)

Q = 0.5 x 0.1 x (20 + 273)

Q = 14.65 W

<h3>Heat current per square meter of the Walls</h3>

QA = W/A

QA = (14.65)/A

Let the area of the wall = 10 cm x 2 cm = 0.1 m x 0.02 m = 0.002 m².

QA = 14.65/0.002

QA = 7,325 W/m²

Learn more about thermal conductivity here: brainly.com/question/11213835

4 0

3 years ago

Define what is meant by restrictive interventions

zzz [600]

Medical movement for disabilities people

5 0

4 years ago