Answer:
0.30581
0.24464
Explanation:
= Coefficient of static friction
= Coefficient of kinetic friction
= 75 N
= 60 N
Normal force

Frictional force

The coefficient of static friction is 0.30581
Kinetic force

The coefficient of kinetic friction is 0.24464
If it starts at rest the initial velocity is 0.
For an acceleration, a, and time, t, the velocity is v=at. Since at t=4, v=7, then a=7/4=1.75m/s^2
Time=50s
speed=25m/s
Distance = speed×time
=25×50
=1250m
DISTANCE TRAVELLED IS =1250m