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andriy [413]
2 years ago
14

What is 1/12+7/9 hj​

Physics
2 answers:
ruslelena [56]2 years ago
7 0

Answer:

31/36

Explanation:

do the math you will see

Umnica [9.8K]2 years ago
6 0

Explanation:

\frac{1}{12}  +  \frac{7}{9}  \\  \\  =  \frac{1 \times 3}{12 \times 3}  +  \frac{7 \times 4}{9 \times 4} \\  \\  =  \frac{3}{36}  +  \frac{28}{36}  \\  \\  =  \frac{3 + 28}{36}  \\  \\  =  \frac{31}{36}  \\  \\   \huge \purple{ \boxed{\therefore \:  \frac{1}{12}  +  \frac{7}{9}  =  \frac{31}{36} }} \\

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 explain why earths acceleration is usually very small compared to the acceleration of the object the earth interact with
Marianna [84]

Answer:

F-ma

Explanation:

If you are speaking of objects like satellites, etc. then their mass is much less than that of the Earth. A good approximation is Newton's first law of motion:

Force = Mass ×  Acceleration

often written:

F = m a

The gravitational force is the same between the Earth and the object - only the mass differs. So the acceleration is inversely proportional to the mass.

6 0
2 years ago
please solve this for me ,A garden roller is pulled with a force of 200N acting at an angle of 50 degree with the ground level.f
Bingel [31]

Answer:

The force pulling the roller along the ground is 128.55 N

Explanation:

A force of 200 N acting at an angle of 50° with the ground level

This force is pulled a garden roller

We need to find the force pulling the roller along the ground

The force that pulling the roller along the ground is the horizontal

component of the force acting

→ The force acting is 200 N at direction 50° with ground (horizontal)

→ The horizontal component = F cosФ

→ F = 200 N , Ф = 50

→ The horizontal component = 200 cos(50) = 128.55 N

128.55 N is the horizontal component of the force that pulling the

roller along the ground

<em>The force pulling the roller along the ground is 128.55 N</em>

8 0
2 years ago
Is james west still alive?
mafiozo [28]
Greetings


and james west is ALIVE

8 0
3 years ago
Read 2 more answers
What is the potential energy of a puppy that weighs 18 N istting in a high chair 2 m high?
kykrilka [37]

Answer:

Potential energy =mass* acceleration due to gravity * height

mass*acceleration due to gravity =weight

hence potential energy of the puppy= weight * height

=18*2

=36 joule

6 0
3 years ago
When a sinusoidal wave with speed 20 m/s , wavelength 35 cm and amplitude of 1.0 cm passes, what is the maximum speed of a point
vova2212 [387]

To solve this problem it is necessary to apply the concepts related to frequency as a function of speed and wavelength as well as the kinematic equations of simple harmonic motion

From the definition we know that the frequency can be expressed as

f = \frac{v}{\lambda}

Where,

v = Velocity \rightarrow 20m/s

\lambda = Wavelength \rightarrow 35*10^{-2}m

Therefore the frequency would be given as

f = \frac{20}{35*10^{-2}}

f = 57.14Hz

The frequency is directly proportional to the angular velocity therefore

\omega = 2\pi f

\omega = 2\pi *57.14

\omega = 359.03rad/s

Now the maximum speed from the simple harmonic movement is given by

V_{max} = A\omega

Where

A = Amplitude

Then replacing,

V_{max} = (1*10^{-2})(359.03)

V_{max} = 3.59m/s

Therefore the maximum speed of a point on the string is 3.59m/s

8 0
3 years ago
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