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Crank
3 years ago
14

Un ciclista en una cuesta hacia abajo, marcha a una velocidad de 45km/h aplica los frenos y al cabo de 5s su velocidad se ha red

ucido a 15km/h, ¿cual es la distancia recorrida durante los 5 segundos?
Physics
1 answer:
nexus9112 [7]3 years ago
8 0

Answer:

Los 0.0416km

esto se debe a que transponemos la fórmula acelerada y obtenemos Distancia = velocidad × tiempo

también recuerda transponer los segundos a horas viendo que la velocidad es por hora

También tenga en cuenta que no hablo español, así que esto fue extremadamente difícil

culto

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Answer:

-9.4 kg m/s

Explanation:

Change in momentum = final momentum − initial momentum

Δp = p − p₀

Δp = -4.3 kg m/s − 5.1 kg m/s

Δp = -9.4 kg m/s

Impulse = change in momentum

J = Δp

J = -9.4 kg m/s

8 0
3 years ago
Hubble's law states that
Maslowich

Answer:

Option (B)

Explanation:

According to Hubble's law, the distance from the earth to the distant galaxies is directly proportional to their recessional velocity (redshift). This means that the more is the distance between the earth and a galaxy, the faster the galaxy is moving away from the earth.

Recessional velocity normally refers to the speed or velocity at which any astronomical body such as a planet, asteroid, star or galaxy moves away from a  reference point, such as from earth.

Thus, the correct answer is option (B).

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In an inelastic collision where does the kinetic energy lost from the objects go? What kind of energy does the kinetic energy tu
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In an inelastic collision, the kinetic energy that is lost can be seen from something such as a car crash. Thermal energy will be significant, in addition to sound energy.

The kinetic energy transforms because of the force exerted on the objects leading to friction and vibration.

7 0
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11) A ball is dropped from the roof to the floor. Its' atoms start vibrating faster.in terms
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Explanation:

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Thermal energy is a form of kinetic energy formed as a result of the movement of the particles of a medium.

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In terms of heat, the ball has transformed kinetic energy into frictional heating after collision causing an increase in temperature after collision.

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3 years ago
A digital audio compact disc carries data, each bit of which occupies 0.6 µm along a continuous spiral track from the inner circ
Maksim231197 [3]

Answer:

Part a)

\omega = 53.85 rad/s

Part b)

\omega = 24.56 rad/s

Part c)

\alpha = -6.55 \times 10^{-3} rad/s^2

Part d)

\theta = 1.75\times 10^5 Rad

Part e)

L = 6262.2 m

Explanation:

Part a)

As we know that speed of the lens is 1.40 m/s

radius of the path is R = 2.60 cm

so angular speed is

\omega = \frac{v}{R}

\omega = \frac{1.40}{0.026}

\omega = 53.85 rad/s

Part b)

radius of the outer path is R = 5.70 cm

so angular speed is

\omega = \frac{v}{R}

\omega = \frac{1.40}{0.057}

\omega = 24.56 rad/s

Part c)

Average angular acceleration is rate of change in angular speed

so it is given as

\alpha = \frac{\omega_f - \omega_i}{\Delta t}

\alpha = \frac{24.56 - 53.85}{(74 \times 60) + 33}

\alpha = \frac{-29.29}{4473}

\alpha = -6.55 \times 10^{-3} rad/s^2

Part d)

For constant angular acceleration the angular displacement is given as

\theta = \frac{\omega_f + \omega_i}{2}\Delta t

\theta = \frac{53.85 + 24.56}{2}(4473)

\theta = 1.75\times 10^5 Rad

Part e)

Total length of the track is given as

L = vt

L = 1.40 \times 4473

L = 6262.2 m

5 0
3 years ago
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