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ollegr [7]
3 years ago
11

Redondear a dos decimales 12,4552​

Physics
1 answer:
NikAS [45]3 years ago
4 0

Answer:

12,46

Explanation:

esto se debe a que el número que está después del 5 en este caso 5 aumenta o eleva el valor aunque si es un número menor a 5 queda igua

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The World-War II battleship U.S.S Massachusetts used 16-inch guns whose barrel lengths were 15 m long. The shells each of mass 1
Vaselesa [24]

Answer:

The explosive force experienced by the shell inside the barrel is 23437500 newtons.

Explanation:

Let suppose that shells are not experiencing any effect from non-conservative forces (i.e. friction, air viscosity) and changes in gravitational potential energy are negligible. The explosive force experienced by the shell inside the barrel can be estimated by Work-Energy Theorem, represented by the following formula:

F\cdot \Delta s = \frac{1}{2}\cdot m \cdot (v_{f}^{2}-v_{o}^{2}) (1)

Where:

F - Explosive force, measured in newtons.

\Delta s - Barrel length, measured in meters.

m - Mass of the shell, measured in kilograms.

v_{o}, v_{f} - Initial and final speeds of the shell, measured in meters per second.

If we know that m = 1250\,kg, v_{o} = 0\,\frac{m}{s}, v_{f} = 750\,\frac{m}{s} and \Delta s = 15\,m, then the explosive force experienced by the shell inside the barrel is:

F = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot \Delta s}

F = \frac{(1250\,kg)\cdot \left[\left(750\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]}{2\cdot (15\,m)}

F = 23437500\,N

The explosive force experienced by the shell inside the barrel is 23437500 newtons.

6 0
2 years ago
Why Study Science? Help me out
Mashutka [201]
All but the last one!
6 0
1 year ago
Read 2 more answers
A particle is moving with SHM of period pie . initially it is 10 cm from The center of the motion and moving in the positive dir
Viefleur [7K]

Answer:

y = 10.44cos(2t - 0.291) cm

Explanation:

y = Acos(2πt/T + φ) = Acos(2πt/π + φ) = Acos(2t + φ)

v = y' = -2Αsin(2t + φ)

10 = Acos(2(0) + φ) = Acosφ

6 = -2Αsin(2(0) + φ) = -2Asinφ

6/10 = -2Asinφ/Acosφ = -2tanφ

tanφ = -0.3

φ = -0.291 radians

10 = Acos(-0.291)

A = 10/cos(-0.291) = 10.44

7 0
3 years ago
Astronauts brought back 500 lb of rock samples from the moon. how many kilograms did they bring back? 1 kg = 2.20 lb 227 kg 227
Aleksandr [31]

Astronauts brought back 227kg of rock samples from the moon.

<h3>Who is an astronaut?</h3>

A person who has been trained, outfitted, and sent into space by a human spaceflight program to serve as a commander or crew member is known as an astronaut (from the Ancient Greek words (astron), meaning "star," and (nautes), meaning "sailor"). The word is occasionally used to refer to anyone who flies into space, including scientists, politicians, journalists, and tourists, despite the fact that it is typically only designated for professional space travelers.

600 astronauts have made space flights since 1961. Up until 2002, only governments—either the military or civilian space agencies—sponsored and educated astronauts. A new class of astronaut was introduced in 2004 with the suborbital flight of the privately funded SpaceShipOne: the commercial astronaut.

Explanation:

1kg=2.20lb

500lb=(1/2.20*500)kg

500lb=227kg

To learn more about astronaut , visit:

brainly.com/question/11244838

#SPJ4

7 0
1 year ago
At what angle should the axes of two polaroids be placed so as to reduce the intensity of the incident unpolarized light to 13.
prohojiy [21]

Answer:

θ = 66.90°

Explanation:

we know that

I= \frac{I_0}{2}cos^2\theta

I= intensity of polarized light =1

I_o= intensity of unpolarized light = 13

putting vales we get

1= \frac{13}{2}cos^2\theta

⇒\theta=cos^{-1} \sqrt{\frac{1}{6.5} }

therefore θ = 66.90°

5 0
3 years ago
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