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4 years ago

10

What is a standard with measuremen?

1 answer:

ZanzabumX [31]4 years ago

6 0

The grammar aha.... not being mean

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Matter's resistance to a change in motion is called

AURORKA [14]

Answer:

Inertia! I hope this helps!

7 0

4 years ago

Read 2 more answers

A rear window defroster consists of a long, flat wire bonded to the inside surface of the window. When current passes through th

GenaCL600 [577]

Answer:

$\rho=1.8\times 10^{-8}\Omega.m$

Explanation:

Given:

width of the wire, $w=1.8\ mm=1.8\times 10^{-3}\ m$

thickness of the flat wire, $d=0.12\ mm=1.2\times 10^{-4}$

length of the wire, $l=12\ m$

voltage across the wire, $V=12\ V$

current through the wire, $I=12\ A$

Now the net resistance of the wire:

using ohm's law

$R=\frac{V}{I}$

$R=\frac{12}{12}$

$R=1\ \Omega$

We have the relation between the resistivity and the resistance as:

$R=\rho.\frac{l}{a}$

where:

a = cross sectional area of the wire

$\rho =$ resistivity of the wire material

$1=\rho\times \frac{12}{1.8\times 10^{-3}\times 1.2\times 10^{-4}}$

$\rho=1.8\times 10^{-8}\Omega.m$

4 0

4 years ago

During take-off a 5kg model rocket, initially at rest, burns fuel for 4.6s causing its speed to increase from rest to 39m/s duri

MrRa [10]

Answer:

The height is "89.61 m". A further explanation is given below.

Explanation:

According to the question,

Mass of rocket,

m = 5 kg

Time,

t = 4.6 s

Initial speed of rod

u = o m/s

Final speed,

v = 39 m/s

drag,

= 60 N

So,

⇒ acceleration, $a=\frac{v-u}{t}$

$=\frac{39-0}{4.6}$

$= 8.478 \ m/s^2$

⇒ $F_{net}= Net \ force$

$=ma$

$=5\times 8.478$

$=42.89 \ N$

Now,

The thrust will be:

⇒ $Thrust-weight-drag=Net \ force$

⇒ $Thrust-(5\times 9.8)-60=42.89$

⇒ $Thrust-49-60=42.89$

⇒ $Thrust-109=42.89$

⇒ $Thrust=42.89+109$

⇒ $Thrust=151.89 \ N$

The height will be:

⇒ $h=\frac{1}{2} at^2$

$=\frac{1}{2}\times 8.47\times (4.6)^2$

$=\frac{1}{2}\times 8.47\times 21.16$

$=89.61 \ m$

5 0

3 years ago

carlis lives 100 m away from his friend home what is his average speed if he reaches his friends home in 50s

Savatey [412]

100m ÷ 50s = 2m/s
Just some simple divison.

8 0

4 years ago

A 81 kg block is released at a 3.8 m height. the track is frictionless. the block travels down the track, hits a massless spring

Alenkinab [10]

Since the track is friction less, blockâ€™s kinetic energy at the bottom of the track is equal to its potential energy at the top of the track.
PE = 81 * 9.8 * 3.8 = 3016.44 J
Work = 1/2 * 1888 * d^2
PE = Kinetic energy at the base.
1/2 * 1888 * d^2 = 3016.44
d = 1.78 approx 1.8
F = Ke = 1888 * 1.8 = 3398.4N

8 0

3 years ago