Explanation:
Given that,
Initial speed of the rock, u = 30 m/s
The acceleration due to gravity at the surface of the moon is 1.62 m/s².
We need to find the time when the rock is ascending at a height of 180 m.
The rock is projected from the surface of the moon. The equation of motion in this case is given by :
It is a quadratic equation, after solving whose solution is given by:
t = 7.53 s
or
t = 8 seconds
(e)If it is decending, v = -20 m/s
Now t' is the time of descending. So,
Let h' is the height of the rock at this time. So,
or
h' = 155 m
Answer:
The details of bands is given in explanation.
Explanation:
The electromagnetic waves are differentiated into different bands based upon their wavelengths and frequencies. The names of different bands are as follows:
1. Radio Waves
2. Micro Waves
3. Infra-red
4. Visible light
5. Ultra Violet
6. X-rays
7. Gamma Rays
<u>The frequency of every region or rays increases from 1 through 7</u>. The <u>energy of rays also increase from 1 through 7</u>. Since, the wave length is inversely related to energy and frequency, thus the <u>wavelength of rays decrease from 1 through 7</u>.
A detailed information of the bands is provided in the picture attached.
Something to do with how the suns magnetic field interacts with the surface plasmas I think.
Given Information:
Magnetic field = B = 1×10⁻³ T
Frequency = f = 72.5 Hz
Diameter of cell = d = 7.60 µm = 7.60×10⁻⁶ m
Required Information:
Maximum Emf = ?
Answer:
Maximum Emf = 20.66×10⁻¹² volts
Explanation:
The maximum emf generated around the perimeter of a cell in a field is given by
Emf = BAωcos(ωt)
Where A is the area, B is the magnetic field and ω is frequency in rad/sec
For maximum emf cos(ωt) = 1
Emf = BAω
Area is given by
A = πr²
A = π(d/2)²
A = π(7.60×10⁻⁶/2)²
A = 45.36×10⁻¹² m²
We know that,
ω = 2πf
ω = 2π(72.5)
ω = 455.53 rad/sec
Finally, the emf is,
Emf = BAω
Emf = 1×10⁻³*45.36×10⁻¹²*455.53
Emf = 20.66×10⁻¹² volts
Therefore, the maximum emf generated around the perimeter of the cell is 20.66×10⁻¹² volts
