Question

If i have 2.9liters of gas at a pressure of 5 atm and a temperature of 50 what will be the temperature of the gas if i decrease the volume of the gas to 2.4 liters and decrease the pressure to 3 atm

Answer 1

Answer:

T₂= FINAL TEMPERATURE  = 160.4 K

Explanation:

Given data:

Initial volume of gas = 2.9 L

Initial pressure = 5 atm

Initial temperature = 50°C

Final volume = 2.5 L

Final pressure = 3 atm

Final temperature = ?

Solution:

First of all we will convert the temperature in kelvin.

273+ 50 = 323 K

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Now we will put values in formula.

P₁V₁/T₁ = P₂V₂/T₂  

T₂  = P₂V₂ T₁ / P₁V₁

T₂ = 3 atm × 2.4 L × 323 K / 5 atm × 2.9  L  

T₂ = 2325.6 atm. L. K / 14.5 atm.L

T₂ = 160.4 K