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otez555 [7]
3 years ago
13

Hello whats the answer to"What is 20 000 Hz In kHz" thanks this for my range of hearing homework

Chemistry
1 answer:
stira [4]3 years ago
8 0

Answer:

=20kHz

.............................

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Compare and contrast nitrogen and phosphorus cycles
azamat

The phosphorous cycle does not include an atmospheric component because phosphorous does not cycle through the atmosphere. In comparison, important processes of the carbon and nitrogen cycle occur in the atmosphere

7 0
3 years ago
En condiciones normales 1g de aire ocupa un volumen de 773 mL ¿ qué volumen ocupará la misma masa de aire a 0 ºC y la presión a
emmainna [20.7K]

Answer:

El volumen que ocupará la misma masa de aire es 839.49 mL.

Explanation:

Las condiciones normales de presión y temperatura (abreviado CNPT) o presión y temperatura normales (abreviado PTN o TPN), son términos que implican que la temperatura referenciada es de 0ºC (273,15 K) y la presión de 1 atm (definida como 101.325 Pa).

La ley de Boyle dice que “El volumen ocupado por una determinada masa gaseosa a temperatura constante, es inversamente proporcional a la presión”  y se matemáticamente como

Presión*Volumen=constante

o P*V=k

La ley de Charles es una ley que dice que cuando la cantidad de gas y de presión se mantienen constantes, el cociente que existe entre el volumen y la temperatura siempre tendrán el mismo valor:  

\frac{V}{T} =k

La ley de Gay-Lussac​ establece que la presión de un volumen fijo de un gas, es directamente proporcional a su temperatura. Se expresa matemáticamente como:

\frac{P}{T} =k

Combinando estas tres leyes se obtiene:

\frac{P*V}{T} =k

Siendo un estado inicial 1 y un estado final 2, la expresión anterior queda determinada como:

\frac{P1*V1}{T1} =\frac{P2*V2}{T2}

En este caso:

  • P1=  101325 Pa
  • V1= 773 mL
  • T1= 273.15 K
  • P2= 93,3 kPa= 93300 Pa
  • V2= ?
  • T2= 0°C= 273.15 K

Reemplazando:

\frac{101325 Pa*773 mL}{273,15 K} =\frac{93300 Pa*V2}{273.15 K}

y resolviendo obtenes:

V2=\frac{273.15 K}{93300 Pa} *\frac{101325 Pa*773 mL}{273,15 K}

V2= 839,49 mL

<u><em>El volumen que ocupará la misma masa de aire es 839.49 mL.</em></u>

8 0
3 years ago
A block has a mass of 325g and a volume of 500mL. What is its density? If water has a density (D=m/v) of 1g/mL, will the block f
Licemer1 [7]

Answer:

A. 0.65g/mL, float

Explanation:

Mass: 325g

Volume: 500mL

D = m/v

D = 325/500

D = 0.65

Therefore, the block has a density of 0.65g/mL and it will float since the density of water is greater than the density of the block.

4 0
4 years ago
The vapor pressure of ethanol is 54.68 mm Hg at 25°C. How many grams of estrogen (estradiol), C18H24O2, a nonvolatile, nonelectr
amm1812

Answer:

30.5 g of estrogen

Explanation:

Lowering vapor pressure formula → P° - P' = P° . Xm

P° → Vapor pressure of pure solvent → 54.68 mmHg

P' → Vapor pressure of solution → 53.46 mmHg

54.68 mmHg - 53.46 mmHg = 54.68 mmHg . Xm

0.0223 = Xm → This is the mole fraction for solute

Moles of solute / Total moles

Total moles = Moles of solute + Moles of solvent

Let's determine the moles of solvent → 228 g / 46.07 g/mol = 4.95 moles

Let's determine the moles of solute

Moles of solute / Moles of solute + 4.95 = 0.0223

Moles of solute = 0.0223 . Moles of solute + 0.110

0.9777 moles of solute = 0.110

Moles of solute = 0.110 / 0.9777 → 0.112

Now we can convert the moles to mass to finish the excersise:

0.112 mol . 272.4 g/mol = 30.5 g

3 0
3 years ago
What does the number prefix tell you in the name of an alkene?
Rina8888 [55]

Answer:

The position of the double bond

Explanation:

7 0
3 years ago
Read 2 more answers
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