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tia_tia [17]
3 years ago
9

Who earned a Nobel Peace Prize for their study of the photoelectric effect?

Chemistry
1 answer:
riadik2000 [5.3K]3 years ago
5 0
ALBERT ENSTIEN !!!!!
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A student conducts an experiment to determine the effect of adding salt on the boiling temperature of water. The results are sho
sineoko [7]

Answer:

The answer to your question is: The first option is correct.

Explanation:

From the data given, we conclude that as the amount of salt increases, the boiling point of water increases.

Options

If salt is added to water, the water will boil at a higher temperature This is the hypothesis for the experiment.

Salt makes water boil. This statement is not true.

If water is boiling, it must have salt added to it. This statement is incorrect, it is not the goal of the experiment.

If salt is added to water, the water will get cloudy There is not evidence of that from the information given.

3 0
3 years ago
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Enzymes are essential to cells because they are responsible to either making or breaking other molecules the cells need. True or
8_murik_8 [283]

Answer:

True is the answer to this question

7 0
3 years ago
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How many moles of potassium are in 78.20 g?
Fynjy0 [20]
The answer to this question would be: 2 mol

To answer this question, you need to know the molecular weight of Potassium. Molecular weight determines how much the weight of 1 mol of a molecule has. 
Potassium or Kalium molecular weight is 39.1 gram/mol. Then, 78.20gram of potassium should be: 78.20g/ (39.1g/mol)= 2 mol
7 0
3 years ago
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At sea level, where the pressure was 104 kPa and temperature 21.1 ºC, a certain mass of air occupies 2.0 m3 . To what volume wil
Romashka [77]

Answer:

The volume of air at where the pressure and temperature are  52 kPa, -5.0 ºC is 3.64 m^3.

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 104 kPa

P_2 = final pressure of gas = 52 kPa

V_1 = initial volume of gas = 2.0m^3

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 21.1^oC=273+21.1=294.1K

T_2 = final temperature of gas = -5.0^oC=273+(-5.0)=268 K

Now put all the given values in the above equation, we get:

\frac{104 kPa\times 2.0m^3}{294.1 K}=\frac{52 kPa\times V_2}{268 K}

V_2=3.64 m^3

The volume of air at where the pressure and temperature are  52 kPa, -5.0 ºC is 3.64 m^3.

3 0
3 years ago
Consider two gases, A and B, are in a container at room temperature.
suter [353]
The rate of reaction would increase because as pressure increases the molecules are more likely to bump into each other leading to a more likely hood of the molecules colliding properly to react leading to an increase in the reaction rate of the substance.
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