Native_Americans_in_the_United_State0000000000000000000000000
Explanation:
3 hours, because for every 50 km equals one hour 150 divided into 50 equals 3
Answer:
c
Explanation:
Science influences society through its knowledge and world view. ... Technology influences society through its products and processes
Hewan peliharaan, seperti ternak, memberi kita makanan, serat, dan kulit. Hewan liar, termasuk burung, ikan, serangga, dan penyerbuk, penting untuk mendukung jaring aktivitas dalam ekosistem yang berfungsi. Populasi tumbuhan dan hewan yang sehat sangat penting bagi kehidupan.
Answer:
The work done is calculated as 
Solution:
As per the question:
Mass of the spaceship, m = 3500 kg
Height of the orbit, h = 220 km
Mass of the earth, 
Height of the higher orbit, h' = 360 km
Radius of the orbit, 
Now,
The work done is given by the change in the gravitational potential energy:
Gravitational Potential Energy, U = 
Now, for the lower orbit:



For upper orbit:



Change in the gravitational Potential energy:

Therefore, the work done:
