is using electrolysis to separate water molecules in hydrogen and oxygen atoms , a physical or chemical change?

Find the direction and magnitude of Ftot, the total force exerted on her by the others, given that the magnitudes F1 and F2 are

Mars2501 [29]

Answer:

θ = 36°

Explanation:

given,

F₁ = 22.8 N

F₂ = 16.6 N

magnitude of force = ?

direction of force = ?

$F = \sqrt{F_1^2 + F_2^2}$

$F = \sqrt{22.8^2 + 16.6^2}$

$F = \sqrt{795.4}$

F = 28.20 N

direction

$\theta = tan^{-1}(\dfrac{F_2}{F_1})$

$\theta = tan^{-1}(\dfrac{16.6}{22.8})$

$\theta = tan^{-1}(0.728)$

θ = 36°

5 0

2 years ago

Calculate the weight of your energy car if it has a mass of 233.85 kg.

lianna [129]

Explanation:

'gerfe4egd4gwdrferdfw14589u99y999q EP and it's not the same thing to say about this is a good day for the next few weeks of age or something else I would have to do it for you and your friends to be the first to see the new album and I am a big deal to the world is not the same thing to say about this one for you and I am a big deal to me that he was the first to see you in a few years back and forth to see the world is not a fan and a few years back and I have to be the best way possible for the next few days later and the other side is the only thing that you can get it right here is the only thing I can get it right here is a great time to get a free download of my life

3 0

2 years ago

The space shuttle orbits 310 km above the surface of the Earth.

MAVERICK [17]

Answer:

44.7 N

Explanation:

The gravitational force between the objects is given by:

$F=G\frac{mM}{r^2}$

where

G is the gravitational constant

m and M are the masses of the two objects

r is the distance between the centres of the two objects

In this problem, we have:

$m=5.0 kg$ is the mass of the sphere

$M=5.98\cdot 10^{24} kg$ is the Earth's mass

$R=6370 km$ is the Earth's radius, while h=310 km is the altitude of the sphere, so the distance of the sphere from Earth's centre is

$r=6370 km+310 km=6680 km=6.68\cdot 10^6 m$

Substituting into the equation, we find

$F=(6.67\cdot 10^{-11})\frac{(5.0 kg)(5.98\cdot 10^{24} kg)}{(6.68\cdot 10^6 m)^2}=44.7 N$

8 0

3 years ago

A speed-time graph is shown below:

alexandr1967 [171]

Answer:

<em>The average acceleration of the object is 0.5 cm/s^2</em>. Answer: A)

Explanation:

<u>Average Acceleration</u>

The average acceleration of a moving object is the rate at which the speed changed over time in a specific period. It can be calculated as follows:

$\displaystyle \bar a=\frac{v_f-v_o}{t}$

Where vf is the final speed, vo is the initial speed and t is the time.

The speed-time shows the speed starts at 0 cm/s and ends at 4 cm/s over the 8 seconds period. The average acceleration is:

$\displaystyle \bar a=\frac{4-0}{8}=0.5$

The average acceleration is 0.5 cm/s^2

A) Correct. The average acceleration is 0.5 cm/s^2

B) Incorrect. The average acceleration is 0.5 cm/s^2

C) Incorrect. The average acceleration is 0.5 cm/s^2

D) Incorrect. The average acceleration is 0.5 cm/s^2

3 0

2 years ago

An object in space is initially stationary relative to the Earth. Then, a force begins acting on the object, starting with a for

11111nata11111 [884]

Answer:

v_f =63 m/s

Explanation:

given,

starting force = 0 N

uniform rate increase to 36 N

time of action of Force = 35 s

mass of the body = 10 Kg

Speed of the object = ?

From the given data

if we plot F-t curve we will get a triangular shape

we know,

Impulse = Area between F-t curve

= (1/2) x base x height

= 0.5 x 35 x 36

= 630 N.s

now use Impulse-momentum theorem

Impulse = change in momentum

630 = 10 x (v_f - vi)

630 = 10 x (v_f - 0)

v_f =63 m/s

Speed of the object at 35 sec is equal to v_f =63 m/s

8 0

3 years ago