As frequency decreases , the wavelength will increase !!
frequency= speed of light ÷ wavelength
( inverse relationship )
It appears to be a <span>spiral shape. </span>
Answer:
See below
Explanation:
You have to heat the calorimeter to 100 C from 20 C
this will take .20 kg * 390 j /kg-C * 80 C = <u>6240 j</u>
You have to heat the mass of water to boiling point (100 C ) from 20C
this will take
.50 kg * 4182 j/kg-C * 80 = <u>167,280 j </u>
AND you have to add enough heat to boil off .03 kg of water:
.03 kg * (2260000 j/kg-C ) =<u> 67,800 j</u>
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Power = joules / sec = (6240 + 167280 + 67800) / 274.8 =<u> 878 watts </u>
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<u>Your answer may differ just a bit for slightly different or rounded values of specific heat or heat of fusion for water .....</u>
The power that the light is able to utilize out of the supply is only 0.089 of the given.
Power utilized = (0.089)(22 W)
= 1.958 W
= 1.958 J/s
The energy required in this item is the product of the power utilized and the time. That is,
Energy = (1.958 J/s)(1 s) = 1.958 J
Thus, the light energy that the bulb is able to produce is approximately 1.958 J.
