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3 years ago

27 points for answering this question

Physics

1 answer:

photoshop1234 [79]3 years ago

5 0

It is the second one, it is longitude and moving up and down so its B.

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Suppose a spring has a relaxed length of 28.3 cm. The simulation refers to this as the natural length. This is the length of the

den301095 [7]

Answer:

Explanation:

Normal length of spring = 28.3 cm

stretched length of spring = 38.2 cm

length of extension = 38.2 - 28.3 = 9.9 cm

= 9.9 x 10⁻² m

force applied to stretch = .55 x 9.8 ( mg )

= 5.39 N

Force constant = force applied / extension

= 5.39 / 9.9 x 10⁻²

= .5444 x 10² N /m

= 54.44 N/m

4 0

3 years ago

The gas sample has a volume of 45.1 μL at 24.7 °C. What is the volume of the gas after the sample is heated to 37.2 °C at consta

likoan [24]

Answer:

V₂ = 46.99 μL.

Explanation:

Given that

V₁ = 45.1 μL

T₁ = 24.7°C = 273 + 24.7 = 297.7 K

T₂ = 37.2°C = 273+37.2=310.2 K

Lets take ,The final volume = V₂

We know that ,the ideal gas equation

If the pressure of the gas is constant ,then we can say that

$\dfrac{V_2}{V_1}=\dfrac{T_2}{T_1}$

${V_2}=V_1\times \dfrac{T_2}{T_1}$

Now by putting the values in the above equation we get

${V_2}=45.1\times \dfrac{310.2}{297.7}\ \mu \ L$

V₂ = 46.99 μL.

The final volume will be 46.99 μL.

7 0

3 years ago

The acceleration vector of a particle in projectile motion ________.

Alex73 [517]

Answer:

Points downward, and its magnitude is 9.8 m/s^2

Explanation:

The motion of a projectile consists of two independent motions:

- A uniform horizontal motion, with constant velocity and zero acceleration. In fact, there are no forces acting on the projectile along the horizontal direction (if we neglect air resistance), so the acceleration along this direction is zero.

- A vertical motion, with constant acceleration g = 9.8 m/s^2 towards the ground (downward), due to the presence of gravity wich "pulls" the projectile downward.

The total acceleration of the projectile is given by the resultant of the horizontal and vertical components of the acceleration. But we said that the horizontal component is zero, therefore the total acceleration corresponds just to its vertical component, therefore it is a vector with magnitude 9.8 m/s^2 which points downward.

4 0

3 years ago

Throw a ball upward from point 0 with an

Mariana [72]

Answer:

69m

Explanation:

4 0

3 years ago

You are riding on a carousel that is rotating at a constant 24 rpm. It has an inside radius of 4 ftand outside radius of 12 ft.

Nookie1986 [14]

Answer:

magnitude of the Coriolis acceleration is 44.235 ft/s² and the direction of the acceleration is along the axis of transmission

Explanation:

Given the data in the question;

Speed of carousel N = 24 rpm

From the diagram below, selected path direction defines the Axis of slip.

Hence, The Coriolis is acting along the axis of transmission

Now, we determine the angular speed ω of the carousel.

ω = 2πN / 60

we substitute in the value of N

ω = (2π × 24) / 60

ω = 2.5133 rad/s

Next, we convert the given velocity from mph to ft/s

we know that; 1 mph = 1.4667 ft/s

$V_{slip$ = 6 mph = ( 6 × 1.4667 ) = 8.8002 ft/s

Now, we determine the magnitude of the Coriolis acceleration

$a_c$ = 2( $V_{slip$ × ω )

we substitute

$a_c$ = 2( 8.8002 ft/s × 2.5133 rad/s )

$a_c$ = 44.235 ft/s²

Hence, magnitude of the Coriolis acceleration is 44.235 ft/s² and the direction of the acceleration is along the axis of transmission

7 0

3 years ago