Ca(OH)2 is a strong base.
It’s name is calcium hydroxide and often it is easy to tell if something is a strong base if it has (OH) in the name.
Microchips I know for sure and some types of glass
Answer:Crop rotation also helps to battle against the forces of erosion. Rotating crops helps to improve soil stability by alternating between crops with deep roots and those with shallow roots. Pests are also deterred by eliminating their food source on a regular basis.
Crop rotation is the practice of growing a series of dissimilar or different types of crops in the same area in sequenced seasons. It is done so that the soil of farms is not used for only one set of nutrients. It helps in reducing soil erosion and increases soil fertility and crop yield.
The goal of crop rotation is to reduce the amount of the pest population present in the soil. Some pathogens that cause diseases survive in the soil from year to year in one form or the other, usually as sclerotia, spores, or hyphae. Rotating to non-host crops prevents the buildup of large populations of pathogens.
Explanation: the answer would be 4
Increases soil fertility. ...
Increases crop yield. ...
Increase in soil nutrients. ...
Reduces soil erosion. ...
Limits concentration of pests and diseases. ...
Reduces the stress of weeds. ...
Improves the soil structure. ...
Reduces pollution.
Answer:
C₂H₅O₂
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 0.25 g
Mass of CO₂ = 0.3664 g
Mass of H₂O = 0.15 g
Empirical formula =?
Next, we shall determine the mass of carbon, hydrogen and oxygen present in the compound. This can be obtained as follow:
For Carbon (C):
Mass of CO₂ = 0.3664 g
Molar mass of CO₂ = 12 + (2×16) = 44 g/mol
Mass of C = 12/44 × 0.3664
Mass of C = 0.1
For Hydrogen (H):
Mass of H₂O = 0.15 g
Molar mass of H₂O = (2×1) + 16 = 18 g/mol
Mass of H = 2/18 × 0.15
Mass of H = 0.02 g
For Oxygen (O):
Mass of C = 0.1 g
Mass of H = 0.02 g
Mass of compound = 0.25 g
Mass of O =?
Mass of O = (Mass of compound) – (Mass of C + Mass of H)
Mass of O = 0.25 – (0.1 + 0.02)
Mass of O = 0.25 –0.12
Mass of O = 0.13 g
Finally, we shall determine the empirical formula for the compound. This can be obtained as follow:
C = 0.1
H = 0.02
O = 0.13
Divide by their molar mass
C = 0.1 / 12 = 0.0083
H = 0.02 / 1 = 0.02
O = 0.13 / 16 = 0.0081
Divide by the smallest
C = 0.0083 / 0.0081 = 1
H = 0.02 / 0.0081 = 2.47
O = 0.008 / 0.008 = 1
Multiply by 2 to express in whole number
C = 1 × 2 = 2
H = 2.47 × 2 = 5
O = 1 × 2 = 2
Thus, the empirical formula for the compound is C₂H₅O₂
Answer:
The paper no longer has smooth edges
The paper has not produced gas when torn
The paper has not changed colours
The paper is still paper with the same chemical makeup
