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Lady_Fox [76]
3 years ago
5

Suppose there are 175 tickets available for a school play.

Mathematics
1 answer:
klio [65]3 years ago
8 0

Answer: 77 tickets

Step-by-step explanation: 175 - 98 = 77

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You have a bag that contains 20 quarters, 20 dimes, and 15 nickels. When randomly selecting two coins with no replacement find t
iogann1982 [59]

Answer:

P(2 quarters) = 19/ (13*16) = 19/208  = 0.0913

Step-by-step explanation:

probability of getting 2 quarters?

ok

first draw:  there are 20 quarters to choose from

second draw: there are 19 quarters left to choose

so Total coins are 65 coins

P(2 quarters) = P( 1st quarter)* P(2nd quarter)

P(2 quarters) =  20/65   *   (19/64)

P(2 quarters) = 4/13 *  19/64

P(2 quarters) = 19/ (13*16) = 19/208

4 0
3 years ago
Mutiply 4y-4w^8-3y^5w^3
sukhopar [10]

Answer:

48y⁶w¹¹

Step-by-step explanation:

[-3y⁵][4y] → -12y⁶

×

[w³][-4w⁸] → -4w¹¹

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48y⁶w¹¹

I am joyous to assist you anytime.

8 0
3 years ago
Change the repeating decimal to a fraction:<br> 0.376376376...
taurus [48]

Answer:

Answer is 3/4

Step-by-step explanation:

3 0
2 years ago
3 An open cone has a vertical angle measuring 40°
belka [17]

Answer:

13.41 cm

Step-by-step explanation:

The radius, height, and HALF of vertical angle makes a triangle.

Where

Radius will be the base of the triangle

Height will be the "height" of the triangle

Top angle will be HALF of vertical angle (40/2 = 20)

From the 20 degree angle, the side "opposite" would be the radius, which is 30. The side "adjacent" would be the height, let it be h.

<em>Which trig ratio relates opposite and adjacent? Yes, that is TAN. Thus we can write:</em>

Tan(20) = opposite/adjacent

Tan(20) = 30/h

h = 30/Tan(20)

h = 13.41

So

The height of the cone would be around 13.41 cm

3 0
3 years ago
10 POINTS!!! FULL ANSWER IN STEP BY STEP FORMAT!!
Lilit [14]
After a little manipulation, the given diff'l equation will look like this:

e^y * dy = (2x + 1) * dx.
                                                             x^2
Integrating both sides, we get e^y = 2------- + x + c, or e^y = x^2 + x + c
                                                               2

Now let x=0 and y = 1, o find c:

e^1 = 0^2 + 0 + c.  So, c = e, and the solution is e^y = x^2 + x + e.
4 0
3 years ago
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