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2 years ago

What are some damages for aftershocks

2 answers:

8 0

The aftershock was responsible for additional damage and casualties, as well as for delaying efforts to free people already trapped beneath rubble. There are also examples of large aftershocks' causing more damage and loss of life than the earthquakes they are associated with.

Mariulka [41]2 years ago

8 0

Some consequences of aftershocks are further worsening structural damage already caused by the earthquake (which leads to further loss of property and lives), building collapses, and moving places that are along fault lines (California for example drifts northward a tiny bit each year).

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A sample of Cd(OH)2 is added to pure water and allowed to come to equilibrium at 25ºC. The concentration of Cd +2 = 1.7 x 10 -5M

Archy [21]

Answer:

$Ksp=2.0x10^{-14}$

Explanation:

Hello there!

In this case, given the solubilization of cadmium (II) hydroxide:

$Cd(OH)_2(s)\rightleftharpoons Cd^{2+}(aq)+2OH^-(aq)$

The solubility product can be set up as follows:

$Ksp=[Cd^{2+}][OH^-]^2$

Now, since we know the concentration of cadmium (II) ions at equilibrium and the mole ratio of these ions to the hydroxide ions is 1:2, we infer that the concentration of the latter at equilibrium is 3.5x10⁻⁵ M. In such a way, the resulting Ksp turns out to be:

$Ksp=(1.7x10^{-5})(3.4x10^{-5})^2\\\\Ksp=2.0x10^{-14}$

Regards!

3 0

3 years ago

4Fe + 3O2  2Fe2O3

LenKa [72]

Oxidation
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6 0

3 years ago

6. A quiet sound exerts a pressure of 4.00 x 10^-8 kPa (kPa= kilopascals, a pressure unit). What is this pressure measured in at

Radda [10]

Answer:

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Explanation:

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3 0

3 years ago

What is the mass of 6.12 moles of arsenic (As)?

Alecsey [184]

The answer is D. 459 g As

5 0

3 years ago

Read 2 more answers

A barium hydroxide solution is prepared by dissolving 1.90 g of Ba ( OH ) 2 in water to make 71.1 mL of solution. What is the co

goldenfox [79]

Answer:

The molarity of this solution is 0.156 M

Explanation:

Step 1: Data given

Mass of Ba(OH)2 = 1.90 grams

Molar mass Ba(OH)2 = 171.34 g/mol

Volume of the solution = 71.1 mL = 0.0711 L

Step 2: Calculate moles Ba(OH)2

Moles Ba(OH)2 = mass Ba(OH)2 / molar mass Ba(OH)2

Moles Ba(OH)2 = 1.90 grams / 171.34 g/mol

Moles Ba(OH)2 = 0.0111 moles

Step 3: Calculate molarity

Molarity solutin = moles Ba(OH)2 / volume solution

Molarity solution = 0.0111 moles / 0.0711 L

Molarity solution = 0.156 M

The molarity of this solution is 0.156 M

6 0

3 years ago