Answer:
this is an example
Explanation:
Yes, the balloon will burst at room temperature.
As we know that, 480 x 7/8 = 420 is the maximum Stretching capacity of the balloon.
b) V. / T. = V/T
Where
V = 480 ml and T. = 5 C(278 K)
And T= 30 C( 303 K)
V = V.T/T.
V = 480 x 303/278
V = 523.1 ml
b)V./V=T./T ?
Where
V = 480 ml and
T = 5 C (278 K)?
And V = 420 ml
T=T.V./V
=278 x 480/420
= 317.17 k
Therefore the balloon will burst at the temperature of 317.17 k
Also learn more
The temperature of 0.5 kg of water is 303 K. It is cooled to 278 K by keeping it in a refrigerator. what is the time taken by water to reach 278 K if 87.5 J of heat is given out in each second? ( specific heat capacity of water is 4200 J/kg K )
The balanced reaction is:
4Fe + 3O2 --> 2Fe2O3
Stoichiometrically:
(1.0 mol Fe)(2 mol Fe2O3 / 4 mol Fe) = 0.50 mol Fe2O3
If the actual yield is only 0.325 mol Fe2O3, the % yield can be calculated by dividing actual by theoretical yield:
0.325 / 0.5 x 100% = 65% yield
Answer: The average kinetic energy of water at 
is 
.
Explanation:
Given: Temperature = 
Kinetic energy is the energy acquired by the molecules of a substance due to its motion.
Formula to calculate average kinetic energy is as follows.
where,
T = temperature
k = Boltzmann constant = 
Substitute the value into above formula as follows.
Thus, we can conclude that the average kinetic energy of water at is .
Answer:
the relation between Kp and Kc is
![\colorbox{red}Kp=Kc{[RT]}^{∆n}](https://tex.z-dn.net/?f=%20%5Ccolorbox%7Bred%7DKp%3DKc%7B%5BRT%5D%7D%5E%7B%E2%88%86n%7D)
where
∆n=no.of moles of gaseous product - no.of moles of gaseous reactant in the balanced chemical equation.
R=universal gas constant
T=temperature.
