Answer:
1. 3.1 moles of silver, Ag.
2. 1.55 moles of Cu(NO₃)₂.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
Cu + 2AgNO₃ —> Cu(NO₃)₂ + 2Ag
From the balanced equation above,
1 mole of Cu reacted to produce 1 mole of Cu(NO₃)₂ and 2 moles of Ag.
1. Determination of the number of mole of silver (Ag) produced.
From the balanced equation above,
1 mole of Cu reacted to produce 2 moles of Ag.
Therefore, 1.55 moles of Cu will react to produce = 1.55 × 2 = 3.1 moles of Ag.
Thus, 3.1 moles of Ag is produced.
2. Determination of the number of mole of copper(II) nitrate, Cu(NO₃)₂ produced.
From the balanced equation above,
1 mole of Cu reacted to produce 1 mole of Cu(NO₃)₂.
Therefore, 1.55 moles of Cu will also react to 1.55 moles of Cu(NO₃)₂.
Thus, 1.55 moles of Cu(NO₃)₂ is produced
