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anastassius [24]
3 years ago
5

3. With which temperature scale is temperature directly proportional to average kinetic energy?

Chemistry
1 answer:
padilas [110]3 years ago
6 0

Answer:

Kelvin  absolute zero

gases and liquids only

Explanation:

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The activation energy for a reaction is changed from 184 kJ/mol to 59.0 kJ/mol at 600. K by the introduction of a catalyst. If t
11111nata11111 [884]

Answer:

The catalyzed reaction will take 2.85 seconds to occur.

Explanation:

The activation energy of a reaction is given by:                                                        

k = Ae^{-\frac{E_{a}}{RT}}

For the reaction without catalyst we have:

k_{1} = Ae^{-\frac{E_{a_{1}}}{RT}}   (1)

And for the reaction with the catalyst:

k_{2} = Ae^{-\frac{E_{a_{2}}}{RT}}   (2)

Assuming that frequency factor (A) and the temperature (T) are constant, by dividing equation (1) with equation (2) we have:                      

\frac{k_{1}}{k_{2}} = \frac{Ae^{-\frac{E_{a_{1}}}{RT}}}{Ae^{-\frac{E_{a_{2}}}{RT}}}

\frac{k_{1}}{k_{2}} = e^{\frac{E_{a_{2}} - E_{a_{1}}}{RT}    

\frac{k_{1}}{k_{2}} = e^{\frac{59.0 \cdot 10^{3}J/mol - 184 \cdot 10^{3} J/mol}{8.314 J/Kmol*600 K} = 1.31 \cdot 10^{-11}    

Since the reaction rate is related to the time as follow:

k = \frac{\Delta [R]}{t}

And assuming that the initial concentrations ([R]) are the same, we have:

\frac{k_{1}}{k_{2}} = \frac{\Delta [R]/t_{1}}{\Delta [R]/t_{2}}

\frac{k_{1}}{k_{2}} = \frac{t_{2}}{t_{1}}

t_{2} = t_{1}\frac{k_{1}}{k_{2}} = 6900 y*1.31 \cdot 10^{-11} = 9.04 \cdot 10^{-8} y*\frac{365 d}{1 y}*\frac{24 h}{1 d}*\frac{3600 s}{1 h} = 2.85 s

Therefore, the catalyzed reaction will take 2.85 seconds to occur.

I hope it helps you!                            

4 0
3 years ago
Give an example of two other body systems that work together and explain how they support each other.
gulaghasi [49]

Answer:

2 examples are cardiovascular and respiratory systems.

7 0
3 years ago
An unknown compound is found to have a molar mass of 392.16 g/mol. If the empirical formula is C2H5PF2, what is the molecular fo
notsponge [240]

Answer:

C8H20P4F8

Explanation:

Molecular formula is based off a ratio of the molecular formula's molar mass divided by the empirical formula's molar mass.

The molar mass of the empirical formula C2H5PF2 is 98.02g. We find this by adding the molar masses of all elements in the formula, multiplied by their subscripts.

2(12.01) + 5(1.01) + 30.97 + 2(18.99) = 98.02

We then divide the molecular molar mass by the empirical molar mass.

392.16/98.02 = 4

This tells us that the molecular formula has 4 times the mass of the empirical formula. Because mass comes from the elements in the formula, we multiply all the subscripts by 4 to get the molecular formula.

2x4 = 8

5x4 = 20

1x4 = 4

2x4 = 8

So the molecular formula is C8H20P4F8

8 0
2 years ago
What is the balanced form of the chemical equation shown below?<br> N2(g) + H2(g) → NH3(g)<br> -
Rom4ik [11]
To balance equations you have to have same number of atoms on both sides of the equation just multiply with a suitable digit

6 0
2 years ago
Someone help me i don’t understand it
Troyanec [42]
Use PV=nRT to help you
3 0
3 years ago
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