Six over eleven the answer to this problem.
In order to solve this problem, we transform the statements into
algebraic expressions. First, we assign the variables.
Let:
x = Gina’s number
y = Sara’s number
For the first equation, we show that Gina’s number is greater
than Sara’s number by 2. For the second equation, we show that the sum of both
numbers is 68.
<span>(1)
</span>x – y = 2
<span>(2)
</span>x + y = 68
<span>We
add the two expressions, which result in the expression: 2x = 70. Then we
divide 70 by 2 to get the value of x. We then have x = 35. Using the second
equation, we solve for y = 68-35. This gives y = 33. To summarize, Gina’s
number is 35 while Sara’s number is 33.</span>
Answer:
Domain {7,-2,4,-9,0} Range {3,-2,1,0,7}
Step-by-step explanation:
Just remember that domain is the x values and the range is the y values.
tan 52 = 180/a; a = 180/tan 52
tan 43 = 180/b; b = 180/tan 43
you need to calculate, a-b = 180/tan 52 - 180/tan 43
substitute the value of tan thetas, and calculate it simply...
Solution
- 89 gallons contains 40 gallons twice such that:
![89=40+40+9](https://tex.z-dn.net/?f=89%3D40%2B40%2B9)
- This means that we can find at least 200% of 40 gallons in 89 gallons. This gives us what to expect.
- To get the percentage we are looking for, we should use the formula:
![\frac{\text{new}}{\text{old}}\times100\text{ \%}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7Bnew%7D%7D%7B%5Ctext%7Bold%7D%7D%5Ctimes100%5Ctext%7B%20%5C%25%7D)
New, in this case, is 89 gallons, Old is 40 gallons.
- Thus, we can calculate the percentage as follows:
![\begin{gathered} \frac{89}{40}\times100 \\ =2.225\times100 \\ =222.5\text{ \%} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B89%7D%7B40%7D%5Ctimes100%20%5C%5C%20%3D2.225%5Ctimes100%20%5C%5C%20%3D222.5%5Ctext%7B%20%5C%25%7D%20%5Cend%7Bgathered%7D)
Thus, the answer is 222.5%